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Bunuel
How many ordered pairs of positive integers (M,N) satisfy the equation \(\frac {M}{6} = \frac{6}{N}\) ?

(A) 6
(B) 7
(C) 8
(D) 9
(E) 10

Cross-multiplying, we see that MN = 36. Notice that if k is a positive factor of 36, then k x (36/k) = 36; therefore (k, 36/k) is one of the ordered pairs we are looking for. Since this is true for any positive factor of 36, the number of such ordered pairs is precisely the number of positive factors of 36.

Since 36 is a perfect square, we see that it has an odd number of factors, and thus the number of ordered pairs must also be odd, so the correct answer is either 7 or 9.

Since 36 = 2^2 x 3^2, it has (2 + 1)(2 + 1) = 9 factors and thus there are 9 ordered pairs (M, N) satisfying the equation.

Answer: D
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Bunuel
How many ordered pairs of positive integers (M,N) satisfy the equation \(\frac {M}{6} = \frac{6}{N}\) ?

(A) 6
(B) 7
(C) 8
(D) 9
(E) 10

Asked: How many ordered pairs of positive integers (M,N) satisfy the equation \(\frac {M}{6} = \frac{6}{N}\) ?

M/6 = 6/N
MN = 36 ; N <>0

36 = 2^2 * 3^2

(M,N) = {(1,36),(2,18),(3,12),(4,9),(6,6),(9,4),(12,3),(18,2),(36,1)}

9 ordered pairs of M & N satisfy the equation

IMO D
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