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GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
05 Jan 2017, 05:00
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (01:10) correct
11%
(01:33)
wrong
based on 107
sessions
History
Date
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Not Attempted Yet
If \(\frac{3^r}{9^2*k^{(-2)}} = 25\), what is r?
(1) k = 5
(2) \(\frac{1}{k^{(-1)}} = k\)
(1) k = 5
(2) \(\frac{1}{k^{(-1)}} = k\)
05 Jan 2017, 08:34
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\(\frac{3^r*k^{(2)}}{3^4} = 25\)
= \(3^{(r - 4)}*k^2 = 5^2\)
= \(3^{(r - 4)} = (5/k)^2\)
St1: k = 5 --> Value of r can be calculated
St2: k = k --> Clearly insufficient
Answer: A
= \(3^{(r - 4)}*k^2 = 5^2\)
= \(3^{(r - 4)} = (5/k)^2\)
St1: k = 5 --> Value of r can be calculated
St2: k = k --> Clearly insufficient
Answer: A
05 Jan 2017, 11:45
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Bunuel
If \(\frac{3^r}{9^2*k^{(-2)}} = 25\), what is r?
(1) k = 5
(2) \(\frac{1}{k^{(-1)}} = k\)
(1) k = 5
(2) \(\frac{1}{k^{(-1)}} = k\)
\(3^r. k^2 = 3^4 . 5^2\)
From Statement 1: \(3^r. 5^2 = 3^4 . 5^2\)
\(3^r = 3^4\) => r =4 . Sufficient
Statement 2 says . k = k . clearly Not sufficient
Answer is A .
