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If 7 people board an airport shuttle with only 3 available seats, how

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Bunuel
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If 7 people board an airport shuttle with only 3 available seats, how [#permalink] New post   02 Jul 2019, 03:21
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If 7 people board an airport shuttle with only 3 available seats, how many different seating arrangements are possible? (Assume that 3 of the 7 will actually take the seats.)

A. 35
B. 180
C. 210
D. 840
E. 5040
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C
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Kinshook
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Re: If 7 people board an airport shuttle with only 3 available seats, how [#permalink] New post   02 Jul 2019, 03:26
Bunuel wrote:
If 7 people board an airport shuttle with only 3 available seats, how many different seating arrangements are possible? (Assume that 3 of the 7 will actually take the seats.)

A. 35
B. 180
C. 210
D. 840
E. 5040


Different seating arrangements = 7 * 6 * 5 = 210

IMO C
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If 7 people board an airport shuttle with only 3 available seats, how [#permalink] New post   Updated on: 02 Jul 2019, 03:51
First possiblity 7, second 6 third 5..= 7×6×5= 210

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Originally posted by Aderonke01 on 02 Jul 2019, 03:26.
Last edited by Aderonke01 on 02 Jul 2019, 03:51, edited 1 time in total.
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Re: If 7 people board an airport shuttle with only 3 available seats, how [#permalink] New post   02 Jul 2019, 03:28
Bunuel wrote:
If 7 people board an airport shuttle with only 3 available seats, how many different seating arrangements are possible? (Assume that 3 of the 7 will actually take the seats.)

A. 35
B. 180
C. 210
D. 840
E. 5040


7 for first seat*6 for 2nd seat *5 for 3rd seat = 210 IMO C
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Re: If 7 people board an airport shuttle with only 3 available seats, how [#permalink] New post   02 Jul 2019, 08:06
Bunuel wrote:
If 7 people board an airport shuttle with only 3 available seats, how many different seating arrangements are possible? (Assume that 3 of the 7 will actually take the seats.)

A. 35
B. 180
C. 210
D. 840
E. 5040


total arragements possible ; 7*6*5 ; 210
IMO C
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Re: If 7 people board an airport shuttle with only 3 available seats, how [#permalink] New post   02 Jul 2019, 13:22
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Bunuel wrote:
If 7 people board an airport shuttle with only 3 available seats, how many different seating arrangements are possible? (Assume that 3 of the 7 will actually take the seats.)

A. 35
B. 180
C. 210
D. 840
E. 5040


Arrangements—> Permutation = 7p3
= 7*6*5
= 210

IMO Option C

Pls Hit kudos if you like the solution

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Re: If 7 people board an airport shuttle with only 3 available seats, how [#permalink] New post   06 Jul 2019, 17:58
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Bunuel wrote:
If 7 people board an airport shuttle with only 3 available seats, how many different seating arrangements are possible? (Assume that 3 of the 7 will actually take the seats.)

A. 35
B. 180
C. 210
D. 840
E. 5040



The number of seating arrangements is 7P3 = 7! / (7 - 3)! = 7! / 4! = 7 x 6 x 5 = 210.

Answer: C
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Re: If 7 people board an airport shuttle with only 3 available seats, how [#permalink]
06 Jul 2019, 17:58
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