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TheUltimateWinner
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Schools: Harvard '24 Judge '23 LBS '24 McCombs '24 Mendoza Tepper '24 Ross '24 Cox Marshall '24 Fisher Kelley '24 Jones McDonough '24 Owen '24 Terry BU Simon '24 Katz GWU Mason Babson Gabelli Foster '24 Goizueta '24 Scheller Stern '23 CBS '23 Booth '23 Haas '25 Wharton '25 Stanford '26 Johnson'23 Fuqua '23 Kellogg '23 Kenan-Flagler'23 INSEAD Aug 22 intake Olin '23 Said '23 Sloan '23 Carey Arizona "22 Yale '23 UC Davis Madison '23 Anderson '23 Carroll Carlson '23 Darden '23
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17 Mar 2019, 08:43
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
45% (02:46) correct
55%
(02:18)
wrong
based on 28
sessions
History
Date
Time
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Not Attempted Yet
If \(a>0\), is \(a>1\)?
(1) \(a*b>a+b\)
(2) \(\frac{a}{b}>\frac{b}{a}\)
(1) \(a*b>a+b\)
(2) \(\frac{a}{b}>\frac{b}{a}\)
17 Mar 2019, 12:20
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If a = 1/10, and b = -10, then both statements are true, but a is not greater than 1. But if a = 3 and b = 2, then again both statements are true and a is greater than 1. So the answer is E.
If you knew b was positive (which we don't) then Statement 1 would be sufficient alone, since if a < 1, ab would be less than b, and therefore less than a+b if a > 0, so it would be impossible for Statement 1 to be true if a < 1 were true, meaning a > 1 (a cannot equal 1 either, for the same reason).
If you knew b was positive (which we don't) then Statement 1 would be sufficient alone, since if a < 1, ab would be less than b, and therefore less than a+b if a > 0, so it would be impossible for Statement 1 to be true if a < 1 were true, meaning a > 1 (a cannot equal 1 either, for the same reason).
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