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50a-100b = 50(a-2b) ----- (1)

from a+b=2 => b=2-a ----(2)

from (1) and (2)
50(a-2(2-a)).. => 50(a-4+2a) = 50 (3a-4)

now from given values I
150 = 50 (3a-4)
3a-4=3
a= 7/3, i.e. a>2... not possible since positive number a+b=2, B can not be -ve

II 100 = 50(3a-4)
3a-4=2
a=2, not possible since positive number a+b=2, b can not be zero

III. 50 = 50(3a-4)
3a-4=1
a=5/4, holds the given statement a=b=2.

Answer is C
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Asked: If a and b are positive numbers such that a + b =2, which of the following could be a value of 50a - 100b ?

b = 2 - a

50a - 100b = 50a - 100(2-a) = 150a - 200

I. 150: 150a - 200 = 150 ; 150a = 350; a = 350/150 = 7/3; b = 2 - 7/3 = -1/3; Not possible
II. 100: 150a - 200 = 100 ; 150a = 300; a = 300/150 = 2; b = 2 - 2 = 0; Not possible
III. 50: 150a - 200 = 50 ; 150a = 250; a = 250/150 =5/3; b = 2 - 5/3 = 1/3; Possible

(A) I only
(B) II only
(C) III only
(D) I and III only
(E) II and III only

IMO C
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The fact that this is a could be value question, with positive number constraint on variables, should ring a bell that you are looking for the valid range for the expression (50a - 100b). This method is called the "boundary sweep"
If a+b=2 and both variables are positive(≠ 0),this means that:
0˂a< 2 ;
0˂b< 2

Substituting b (=2-a) on 50a - 100b you get
50a - 100 (2-a)
150a-200

If you test the upper and lower limit for a in the above expression, you get :
150(2) -200 = 100
150 (0) -200 = -200

This means:
-200˂ 150a-200 <100

Since the extremes arent valid, the only value within the range is 50 .
Answer (C) III only.
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