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Bunuel
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Bunuel
If a and b are two consecutive integers, then what is the value of a?

(1) ab = 6
(2) 3^a > 1

#1
x*(x+1)=6
solve we get
so a = -3 or -2 or 3,2
A,b not defined

insufficient
#2
3^a>1 so a =1,2,3,4 so on insufficeint
from 1 & 2
a has to be +ve so a = 2or3
IMO E
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a = ?

a and be are consecutive integers, therefore b = a + 1

St 1: ab = 6 ==> a(a+1) = 6 ==> \(a^{2}\)+a-6= 0 ==> (a+3)(a-2)=0 ==> a = -3 or 2 ==> not sufficient since we have two values for a
St 2: \(3^{a}\)> 1 ==> a > 0 ==> Not sufficient since there infinite numbers greater than zero

St 1 and St 2 combined ==> a = 2 ==> sufficient (answer is C)
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Archit3110
Bunuel
If a and b are two consecutive integers, then what is the value of a?

(1) ab = 6
(2) 3^a > 1

#1
x*(x+1)=6
solve we get
so a = -3 or -2 or 3,2
A,b not defined

insufficient
#2
3^a>1 so a =1,2,3,4 so on insufficeint
from 1 & 2
a has to be +ve so a = 2or3
IMO E

The question stated that a and b are two consecutive integers. The only possibility for a can be 2. How it can be 3? Can you please explain?
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I also initially thought the answer was C based on another question posted by Bunuel for almost the exact same wording. https://gmatclub.com/forum/if-a-and-b-a ... fl=similar

I realized that the key here is that the statement says that a and b are consecutive integers but it does not specify which one is the smaller/larger of the two. So b could be the smaller number. Hence ab = 6 could be 2*3 = 6 OR 3*2 = 6 (and the negatives of each of these as well).

SwamyGali18
Archit3110
Bunuel
If a and b are two consecutive integers, then what is the value of a?

(1) ab = 6
(2) 3^a > 1

#1
x*(x+1)=6
solve we get
so a = -3 or -2 or 3,2
A,b not defined

insufficient
#2
3^a>1 so a =1,2,3,4 so on insufficeint
from 1 & 2
a has to be +ve so a = 2or3
IMO E

The question stated that a and b are two consecutive integers. The only possibility for a can be 2. How it can be 3? Can you please explain?
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