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Bunuel
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Bunuel
22
a3
+ 4b
____
90

If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 2b ?

A. 2
B. 7
C. 9
D. 11
E. 12


Can we have a and b in their right positions? It looks like 4b is positioned to the right of the 4 digits above.
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KS15
Bunuel
22
a3
+ 4b
____
90

If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 2b ?

A. 2
B. 7
C. 9
D. 11
E. 12


Can we have a and b in their right positions? It looks like 4b is positioned to the right of the 4 digits above.

These are just 3 numbers added to each other.
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Answer: E
2+3+b = 10 since b in a single digit and units place need to have 0 it has to be 10
Therefore, b = 5
1(from carry over)+2+a+4 = 9 => a+7 = 9 => a=9-7=2
a = 2
Substituting the values into the Question : a+2b = 2 + 2(5) = 2+10 = 12
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22
a3
+ 4b
____
90

b can only be 5, 3+2+b=10 , 2+a+4+1(carry forward)=9;a=2

a+2b= 2+2*5= 12, Answer E
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Bunuel
22
a3
+ 4b
____
90

If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 2b ?

A. 2
B. 7
C. 9
D. 11
E. 12

Bunuel does the question actually appear with 4b shifted to the right? If it is I can understand why- yes this problem can still be solved because the question is really just asking if a and b represent the tens and ones place of two two-digit numbers, respectively, then what is a + 2b? Though, I can see why this would certainly mislead some test takers




Can we have a and b in their right positions? It looks like 4b is positioned to the right of the 4 digits above.


Anyways, because a and b must be single positive integers

22 + (2)3 + 4(5)
a= 2
b= 5

2 + 2(5) = 12

Therefore
"E"
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Bunuel
22
a3
+ 4b
____
90

If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 2b ?

A. 2
B. 7
C. 9
D. 11
E. 12

22
a3
4b
____
90
____

Here, 2 + 3 + b = 0

So, b = 5

Again,we have 2 + a + 4 + 1 = 9

So, a = 2

Now, a + 2b = 2 + 5*2 => 12

Thus, answer must be (E)
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