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10 May 2017, 02:32
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If a + b = 5c, then which of the following represents the average (arithmetic mean) of a, b, and c, in terms of c?
A. 3c + 1
B. 2c
C. 5c
D. c/3
E. 3c/2
A. 3c + 1
B. 2c
C. 5c
D. c/3
E. 3c/2
sashiim20
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10 May 2017, 02:42
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If a + b = 5c, then which of the following represents the average (arithmetic mean) of a, b, and c, in terms of c?
a+b = 5c
Average of a,b,c = \(\frac{a+b+c}{3}\)
= \(\frac{5c+c}{3}\) (given a+b = 5c)
= \(\frac{6c}{3}\) = 2c ... Answer B
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a+b = 5c
Average of a,b,c = \(\frac{a+b+c}{3}\)
= \(\frac{5c+c}{3}\) (given a+b = 5c)
= \(\frac{6c}{3}\) = 2c ... Answer B
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Updated on: 19 Jan 2020, 13:47
Originally posted by BrentGMATPrepNow on 10 May 2017, 06:03.
Last edited by BrentGMATPrepNow on 19 Jan 2020, 13:47, edited 1 time in total.
Last edited by BrentGMATPrepNow on 19 Jan 2020, 13:47, edited 1 time in total.
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Bunuel
If a + b = 5c, then which of the following represents the average (arithmetic mean) of a, b, and c, in terms of c?
A. 3c + 1
B. 2c
C. 5c
D. c/3
E. 3c/2
A. 3c + 1
B. 2c
C. 5c
D. c/3
E. 3c/2
We can solve questions like this (VIACs - Variables in the Answer Choices) by using algebra (as sashiim20 has done), or by using the INPUT-OUTPUT approach.
Let's use the INPUT-OUTPUT approach
First find numbers that meet the given condition: a + b = 5c
One option is a = 0, b = 5 and c = 1
Given these values, the average of a, b and c = (0 + 5 + 1)/3 = 2
So, when we INPUT a = 0, b = 5 and c = 1, the OUTPUT (the average of a, b and c) is 2
In this question, we care only about the value of c.
So, let's take the answer choices and plug in c = 1, and see which one yields an OUTPUT of 2
A. 3(1)+ 1 = 4 Not a match. ELIMINATE
B. 2(1) = 2 a match. KEEP
C. 5(1) = 5 Not a match. ELIMINATE
D. c = 1/3 = 1/3 Not a match. ELIMINATE
E. 3(1)/2 = 3/2 Not a match. ELIMINATE
Answer:
