To find which ratio of defect per runs is greater it is to be identified whether d1 > or < d2 and r1 > or < r2 individually. Of course d1 < r1 and d2 < r2
(1) d1 > d2
Clearly, INSUFFICIENT.
(2) r2 > r1
Clearly, INSUFFICIENT.
Together Statement 1) and 2).
Refer table snapshot.
Thus, for sufficiency of \(\frac{d1}{r1} > \frac{d2}{r2}\), d1 > d2 and r1 < r2 – Case 1.
And for sufficiency of \(\frac{d1}{r1} < \frac{d2}{r2}\), d1 < d2 and r1 > r2 – Case 4.
I.e. for a ratio to be greater than other numerator has to be greater than the other and denominator should be lesser than the other.
Answer (C).
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