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Updated on: 31 Jan 2016, 22:11
Originally posted by MathRevolution on 28 Jan 2016, 18:41.
Last edited by Bunuel on 31 Jan 2016, 22:11, edited 1 time in total.
Last edited by Bunuel on 31 Jan 2016, 22:11, edited 1 time in total.
Added the OA.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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84% (01:30) correct
16%
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If each of 3 digit code is formed of integers from 1 to 20, inclusively, and each of the digits are different, how many possible codes are there?
A. 6,040
B. 6,840
C. 6,240
D. 6,340
E. 8,440
* A solution will be posted in two days.
A. 6,040
B. 6,840
C. 6,240
D. 6,340
E. 8,440
* A solution will be posted in two days.
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28 Jan 2016, 23:02
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Code consists of 3 digits and no digit is repeated.
First digit of the code can have 20 possibilities
Second digit can have 19 possibilities
Third digit can have 18 possibilities
Total number of possible codes = 20*19*18 = 6840
Answer: B
First digit of the code can have 20 possibilities
Second digit can have 19 possibilities
Third digit can have 18 possibilities
Total number of possible codes = 20*19*18 = 6840
Answer: B
31 Jan 2016, 19:21
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If each of 3 digit code form integers from 1 to 20, inclusively, and each of the digits are different, how many possible codes are there?
A. 6,040 B. 6,840 C. 6,240 D. 6,340 E. 8,440
--> 20*19*18=6,840. Therefore, the answer is B.
A. 6,040 B. 6,840 C. 6,240 D. 6,340 E. 8,440
--> 20*19*18=6,840. Therefore, the answer is B.
