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Bunuel
If \(h(x) = 2x^3 - 3\) and \(h(m) = -19\), what is the value of m?

(A) –3
(B) –2
(C) 2
(D) 6,856
(E) 6,862

\(h(x) = 2x^3 - 3\) and \(h(m) = -19\)

=> \(2m^3 - 3 = -19\)

=> \(2m^3 = -19 + 3 = -16\)

=> \(m^3 = -8\)

=> m = -2

Hence option B
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h(x) = 2x^3-3
h(m) = -19

h(m) = 2m^3-3
2m^3-3 = -19
2m^3 = -19+3
2m^3 = -16
m^3 = -16/2
m^3 = -8
m = -2

Hence IMO B
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Bunuel
If \(h(x) = 2x^3 - 3\) and \(h(m) = -19\), what is the value of m?

(A) –3
(B) –2
(C) 2
(D) 6,856
(E) 6,862

2m^3-3 = -19
2m^3 = -19+3 = -16
m^3 = -8
m=-2

IMO B
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Given that \(h(x) = 2x^3 - 3\) and \(h(m) = -19\) and we need to find the value of m

To find h(m) we need to compare what is inside the bracket () in h(m) and h(x)

=> We need to substitute x with m in \(h(x) = 2x^3 - 3\) to get the value of h(m)

=> \(h(m) = 2m^3 - 3\) = -19 (given)
=> \(2m^3\) = -19 + 3 = -16
=> \(m^3\) = \(\frac{-16}{2}\) = -8 = \((-2)^3\)
=> m = -2

So, Answer will be B
Hope it helps!

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