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# If, in the addition problem above, a, b, c, d, e, f, x, y, a

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Manager
Joined: 30 Jul 2007
Posts: 130
If, in the addition problem above, a, b, c, d, e, f, x, y, a [#permalink]

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18 Aug 2008, 10:21
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a b c
d e f
-----
x y z

If, in the addition problem above, a, b, c, d, e, f, x, y, and z each represent different positive single digits, what is the value of z ?

(1) 3a = f = 6y

(2) f – c = 3
Director
Joined: 12 Jul 2008
Posts: 513
Schools: Wharton

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18 Aug 2008, 10:26
sarzan wrote:
a b c
d e f
-----
x y z

If, in the addition problem above, a, b, c, d, e, f, x, y, and z each represent different positive single digits, what is the value of z ?

(1) 3a = f = 6y

(2) f – c = 3

C

Need to know c and f.

(1) Insufficient

y = 1 (anything greater than that, and f is a double digit number)
f = 6
a = 2

(2) Insufficient

f could 3-9, c could be 0-6.

(1) and (2) Sufficient

f = 6
6 - c = 3
c = 3
Director
Joined: 12 Jul 2008
Posts: 513
Schools: Wharton

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18 Aug 2008, 10:42
sarzan wrote:
zoinnk wrote:
sarzan wrote:
a b c
d e f
-----
x y z

If, in the addition problem above, a, b, c, d, e, f, x, y, and z each represent different positive single digits, what is the value of z ?

(1) 3a = f = 6y

(2) f – c = 3

C

Need to know c and f.

(1) Insufficient

y = 1 (anything greater than that, and f is a double digit number)
f = 6
a = 2

(2) Insufficient

f could 3-9, c could be 0-6.

(1) and (2) Sufficient

f = 6
6 - c = 3
c = 3

No, thats not it.

Sorry, I didn't read the question carefully. I didn't see that the numbers are distinct.

A

In that case:
2 b c
d e 6
-----
x 1 z

The only possibilities that work are:
2 7 3
5 4 6
-----
8 1 9

or

2 4 3
5 7 6
-----
8 1 9
Manager
Joined: 30 Jul 2007
Posts: 130

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18 Aug 2008, 10:53
[/quote]

Sorry, I didn't read the question carefully. I didn't see that the numbers are distinct.

A

In that case:
2 b c
d e 6
-----
x 1 z

The only possibilities that work are:
2 7 3
5 4 6
-----
8 1 9

or

2 4 3
5 7 6
-----
8 1 9[/quote]

But why did you pick y=1?
Director
Joined: 12 Jul 2008
Posts: 513
Schools: Wharton

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18 Aug 2008, 11:23
sarzan wrote:

Sorry, I didn't read the question carefully. I didn't see that the numbers are distinct.

A

In that case:
2 b c
d e 6
-----
x 1 z

The only possibilities that work are:
2 7 3
5 4 6
-----
8 1 9

or

2 4 3
5 7 6
-----
8 1 9

But why did you pick y=1?

I explained that in my first post:

y = 1 (anything greater than that, and f is a double digit number)
f = 6
a = 2

Last edited by zonk on 18 Aug 2008, 12:42, edited 2 times in total.
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