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14 Aug 2019, 00:16
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B
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Difficulty:
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79% (01:38) correct
21%
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based on 103
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If k is the average (arithmetic mean) of the first 8 positive multiples of 6 greater than 6, and if p is the median of the first 8 positive multiples of 6 greater than 6, what is the value of k/p ?
A. 10/11
B. 1
C. 11/10
D. 12/11
E. 0
A. 10/11
B. 1
C. 11/10
D. 12/11
E. 0
14 Aug 2019, 04:03
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12,18,24,30,36,42,48,54
Median:(36+30) ÷2=33
(54+48+...12)/8=33
So,k/p=1
Option B
Posted from my mobile device
Median:(36+30) ÷2=33
(54+48+...12)/8=33
So,k/p=1
Option B
Posted from my mobile device
18 Aug 2019, 19:29
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Bunuel
If k is the average (arithmetic mean) of the first 8 positive multiples of 6 greater than 6, and if p is the median of the first 8 positive multiples of 6 greater than 6, what is the value of k/p ?
A. 10/11
B. 1
C. 11/10
D. 12/11
E. 0
A. 10/11
B. 1
C. 11/10
D. 12/11
E. 0
We see that the set of the first 8 positive multiples of 6 greater than 6 is an evenly-spaced set. For any evenly-spaced set, the mean and the median are equal.
Since the median and the mean of the first 8 positive multiples of 6 greater than 6 are equal, k/p = 1.
Answer: B
