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Actualy, I got it wrong but realised soon that why am I wrong.

R = {p/(p+q)}*30 + {q/(p+q)}*90 --> 30 * [{p/(p+q)} + {3q/(p+q)}] --> 30 * { (p+3q)/(p+q)} --> 30* { (p+q+2q)/(p+q) } --> 30 * { (p+q)/(p+q) + 2q/(p+q) } --> 30* {1 + 2q/(p+q)} --> 30 + {60q/(p+q)} --> now by plugging in +ve numbers and we know that p<q so, let's take p =1 & q = 2 --> 30 + {60 *2/(1+2)} --> 30 + 120/3 --> 30 + 40 --> R = 70, but it isn't in the choices and also from this we can see that answers can't be less than 70, so eliminate options A, B, and C.
Let's quickly try other numbers e.g. next ones p = 1 , q = 3 --> R = 30 + {60*3/(1+3)} --> R = 30 + 180/4 --> R = 30 + 45 --> R = 75 and it is one of the choices, which is D

Or another simple quick way can be by just plugging in the numbers directly into the equation.

R = p/(p+q) * 30 + q/(p+q) * 90 --> as p<q, let's try p = 1 & q = 2 --> R = 1/(1+2) * 30 + 2/(1+2) * 90 = R = 1/3 * 30 + 2/3 * 90 --> R = 10 + 60 --> R = 70 not one of the choices and also all the choices with less than 70 eliminated and we are left with D & E....
This time with p = 1 & q = 3 --> R = p/(p+q) * 30 + q/(p+q) * 90 --> R = 1/(1+3) * 30 + 3/(1+3) * 90 --> R = 1/4 * 30 + 3/4 * 90 --> R = 1/4 (30 + 3 * 90) --> R = 1/4 (30 + 3 * 90) --> R = 1/4 (30 + 270) --> R = 1/4 (300) --> R = 75 ... matching choice D

And, the mistake I did in a hurry was that I forgot 30 in here 30 + {60q/(p+q)} and just went with plugging in the numbers because of which went for 45, which is B but of course wrong. So, don't get excited that it seems easy and may end up getting it wrong in a hurry.
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Atifs- With P = 1 and Q =2; You arrived at R =70, But how R cannot be less than 70?
P,Q, R - are just positive - they may not be integers.
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Atifs- With P = 1 and Q =2; You arrived at R =70, But how R cannot be less than 70?
P,Q, R - are just positive - they may not be integers.

Yeah, you are right, they can be fraction numbers too. A bit naive of me :|
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Question is tricky because it asks about R, but really you are looking at a soltion that fits the condition of Q and P.
30(p+3q)/(p+q) = R

r=75
75/30 = 5/2
(p+3q)/(p+q) = 5/2
5p+5q = 2p+6q

3p=q --> fits the condition that q>p
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