Quote:
If t, p, and q are different positive integers, how many positive integers are factors of t?
(1)\(t=p∗q;\) p and q have no common prime factors.
(2)\(t=p∗q;\) p and q each have exactly 5 positive integer factors.
(1)\(t=p∗q;\) p and q have no common prime factors.
We can't arrive to the number of factors of q with this information.
p can be 2 and q can be 3.
This would make t = 6, number of factors would be 4 (1,2,3 and 6)
Or p can be 4 and q can be 3
This would make t = 12, number of factors would be 6 (1,2,3,4,6 and 12)
Insufficient.(2)\(t=p∗q;\) p and q each have exactly 5 positive integer factors.
Let N be a number. N = \(a^x b^y c^z\) , where a, b and c are different prime numbers.
The number of factors of N = \((x+1)*(y+1)*(z+1)\)
Now, for a positive number to have odd number of factors, it needs to be a perfect square.
since both p and q have 5 factors and both are
different (given in stem), they must be fourth powers of different primes.
let \(p = a^4\) and \(q = b^4\) where both a and b are distinct primes.
Now \(t = p*q = a^4 * b^4\)
So the number of factors t will have =\((4+1) * (4+1) = 25\)
Sufficient.Hence
(B)