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If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

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If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 15 Jun 2016, 03:30
3
10
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A
B
C
D
E

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Question Stats:

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If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2

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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 15 Jun 2016, 04:31
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


before attempting this question simplify it:
\(\frac{z*(2x+y)}{(2xz-y)}\)

We can see that we do not get value of z from (1)

We can see that we do not get value of x and y from (2)

Also after combining we get the value of numerator but not denominator.

E is the answer.
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 06 Dec 2016, 18:19
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AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


We can start by simplifying the question:

(2xz + yz)/(2xz – y) = ?

z(2x + y)/(2xz – y) = ?

Statement One Alone:

2x + y = 3

Although statement one provides a value for 2x + y, we still do not have a value for z or 2xz –y. Thus, statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

z = 2

Although statement two provides a value for z, we still do not have a value for 2xz – y or 2x + y. Thus, statement two alone is not sufficient to answer the question. We can eliminate answer choice B.

Statements One and Two Together:

Using statements one and two, we have values for z and 2x + y. However, since we still do not have a value for 2xz - y, we do not have enough information to answer the question.

Answer: E
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 12 Dec 2016, 14:06
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I read this question as Y = 2xz and I ended up with undefined.
:(
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 22 Dec 2016, 05:42
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AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


\(\frac{(2xz + yz)}{(2xz – y)}\)=\(\frac{z(2x+y)}{(2xz-y)}\)

1) 2x + y = 3
No information about\(\frac{z}{(2xz – y)}\)

2) z = 2
No information about \(\frac{(2x+y)}{(2xz-y)}\)

1) & 2) combined
No information about denominator 2xz-y

E :D
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 21 Jan 2018, 02:59
JeffTargetTestPrep wrote:
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


We can start by simplifying the question:

(2xz + yz)/(2xz – y) = ?

z(2x + y)/(2xz – y) = ?

Statement One Alone:

2x + y = 3

Although statement one provides a value for 2x + y, we still do not have a value for z or 2xz –y. Thus, statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

z = 2

Although statement two provides a value for z, we still do not have a value for 2xz – y or 2x + y. Thus, statement two alone is not sufficient to answer the question. We can eliminate answer choice B.

Statements One and Two Together:

Using statements one and two, we have values for z and 2x + y. However, since we still do not have a value for 2xz - y, we do not have enough information to answer the question.

Answer: E


Hi Jeff,

I understand that statement 1 & 2 alone are not sufficient but I opted for C in this way

From statement 2 we get z=2
denominator becomes 4x-y
=> 2x^2 -1y^2
=> (2x+y) (2x-y)

And numerator becomes 2(2x+y)

2x+y cancels out from both numerator and denominator

now we are left with 2/2x-y

from statement 1 we get 2x+y = 3
=> y=3-2x

putting value of y in 2/2x-y

we get 2/2x-3-2x
which comes up to 2/-3

I know this must be one of the silliest question you have encountered but can`t help myself with this.

your help will be highly appreciated.

Thanks in advance!
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 21 Jan 2018, 23:30
marwahshubham wrote:
JeffTargetTestPrep wrote:
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


We can start by simplifying the question:

(2xz + yz)/(2xz – y) = ?

z(2x + y)/(2xz – y) = ?

Statement One Alone:

2x + y = 3

Although statement one provides a value for 2x + y, we still do not have a value for z or 2xz –y. Thus, statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

z = 2

Although statement two provides a value for z, we still do not have a value for 2xz – y or 2x + y. Thus, statement two alone is not sufficient to answer the question. We can eliminate answer choice B.

Statements One and Two Together:

Using statements one and two, we have values for z and 2x + y. However, since we still do not have a value for 2xz - y, we do not have enough information to answer the question.

Answer: E


Hi Jeff,

I understand that statement 1 & 2 alone are not sufficient but I opted for C in this way

From statement 2 we get z=2
denominator becomes 4x-y
=> 2x^2 -1y^2
=> (2x+y) (2x-y)



Thanks in advance!


Hi

The highlighted part. I think what you have done here is not correct. 4x - y cannot be written as (2x)^2 - y^2
Instead 4x = (2√x)^2 and y = (√y)^2, so we can write 4x - y as (2√x + √y)(2√x - √y)

So the answer will be E only
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 22 Apr 2018, 06:20
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2



ok here is my reasoning

statement one: x could be 0, or 1 and y could be 3 or 1

statement two: clrealy is not enough as we dont know values of x and y

combing the two statements is not enough because we still dont know values of x and y

is my reasong correct ? :) can anyone comment :)
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 22 Apr 2018, 11:10
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dave13 wrote:
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2



ok here is my reasoning

statement one: x could be 0, or 1 and y could be 3 or 1

statement two: clrealy is not enough as we dont know values of x and y

combing the two statements is not enough because we still dont know values of x and y

is my reasong correct ? :) can anyone comment :)


Hello Dave

Generally speaking, in these type of questions, its not a good idea to go by this approach (that we need all values to answer this question), as sometimes we can get an answer without getting values of each and every variable. Its about manipulating the algebraic expressions.

Eg,, lets consider that we have to find this: (2xy - yz)/(4z - 8x)
Do we need to find values of each of x, y, z to solve the above. No. Because we can manipulate the above expression by taking out 'y' common from the numerator and '-4' common from the denominator.

So, it becomes y*(2x-z)/-4*(2x-z). Now 2x-z cancels out from both numerator and denominator and we are left with: y/-4 or -y/4. So what I am trying to say is that to find (2xy - yz)/(4z - 8x), we just need the value of y, values of x and z are NOT required.
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 22 Apr 2018, 12:59
amanvermagmat wrote:
dave13 wrote:
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2



ok here is my reasoning

statement one: x could be 0, or 1 and y could be 3 or 1

statement two: clrealy is not enough as we dont know values of x and y

combing the two statements is not enough because we still dont know values of x and y

is my reasong correct ? :) can anyone comment :)


Hello Dave

Generally speaking, in these type of questions, its not a good idea to go by this approach (that we need all values to answer this question), as sometimes we can get an answer without getting values of each and every variable. Its about manipulating the algebraic expressions.

Eg,, lets consider that we have to find this: (2xy - yz)/(4z - 8x)
Do we need to find values of each of x, y, z to solve the above. No. Because we can manipulate the above expression by taking out 'y' common from the numerator and '-4' common from the denominator.

So, it becomes y*(2x-z)/-4*(2x-z). Now 2x-z cancels out from both numerator and denominator and we are left with: y/-4 or -y/4. So what I am trying to say is that to find (2xy - yz)/(4z - 8x), we just need the value of y, values of x and z are NOT required.


amanvermagmat many thanks for explanation. one question how from this (2xz + yz)/(2xz – y) you got this (2xy - yz)/(4z - 8x) ?
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?  [#permalink]

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New post 22 Apr 2018, 21:53
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many thanks for explanation. one question how from this (2xz + yz)/(2xz – y) you got this (2xy - yz)/(4z - 8x) ?[/quote]

Hello Dave

I didnt get (2xy - yz)/(4z - 8x) from (2xz + yz)/(2xz – y).. I was just giving you a different example to explain my point.
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? &nbs [#permalink] 22 Apr 2018, 21:53
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