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If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

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If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? [#permalink]

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If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2
[Reveal] Spoiler: OA

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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? [#permalink]

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New post 15 Jun 2016, 03:31
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


before attempting this question simplify it:
\(\frac{z*(2x+y)}{(2xz-y)}\)

We can see that we do not get value of z from (1)

We can see that we do not get value of x and y from (2)

Also after combining we get the value of numerator but not denominator.

E is the answer.
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? [#permalink]

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New post 06 Dec 2016, 17:19
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AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


We can start by simplifying the question:

(2xz + yz)/(2xz – y) = ?

z(2x + y)/(2xz – y) = ?

Statement One Alone:

2x + y = 3

Although statement one provides a value for 2x + y, we still do not have a value for z or 2xz –y. Thus, statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

z = 2

Although statement two provides a value for z, we still do not have a value for 2xz – y or 2x + y. Thus, statement two alone is not sufficient to answer the question. We can eliminate answer choice B.

Statements One and Two Together:

Using statements one and two, we have values for z and 2x + y. However, since we still do not have a value for 2xz - y, we do not have enough information to answer the question.

Answer: E
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? [#permalink]

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New post 12 Dec 2016, 13:06
I read this question as Y = 2xz and I ended up with undefined.
:(
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? [#permalink]

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AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


\(\frac{(2xz + yz)}{(2xz – y)}\)=\(\frac{z(2x+y)}{(2xz-y)}\)

1) 2x + y = 3
No information about\(\frac{z}{(2xz – y)}\)

2) z = 2
No information about \(\frac{(2x+y)}{(2xz-y)}\)

1) & 2) combined
No information about denominator 2xz-y

E :D
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? [#permalink]

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New post 21 Jan 2018, 01:59
JeffTargetTestPrep wrote:
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


We can start by simplifying the question:

(2xz + yz)/(2xz – y) = ?

z(2x + y)/(2xz – y) = ?

Statement One Alone:

2x + y = 3

Although statement one provides a value for 2x + y, we still do not have a value for z or 2xz –y. Thus, statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

z = 2

Although statement two provides a value for z, we still do not have a value for 2xz – y or 2x + y. Thus, statement two alone is not sufficient to answer the question. We can eliminate answer choice B.

Statements One and Two Together:

Using statements one and two, we have values for z and 2x + y. However, since we still do not have a value for 2xz - y, we do not have enough information to answer the question.

Answer: E


Hi Jeff,

I understand that statement 1 & 2 alone are not sufficient but I opted for C in this way

From statement 2 we get z=2
denominator becomes 4x-y
=> 2x^2 -1y^2
=> (2x+y) (2x-y)

And numerator becomes 2(2x+y)

2x+y cancels out from both numerator and denominator

now we are left with 2/2x-y

from statement 1 we get 2x+y = 3
=> y=3-2x

putting value of y in 2/2x-y

we get 2/2x-3-2x
which comes up to 2/-3

I know this must be one of the silliest question you have encountered but can`t help myself with this.

your help will be highly appreciated.

Thanks in advance!
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Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)? [#permalink]

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New post 21 Jan 2018, 22:30
marwahshubham wrote:
JeffTargetTestPrep wrote:
AbdurRakib wrote:
If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?

1) 2x + y = 3
2) z = 2


We can start by simplifying the question:

(2xz + yz)/(2xz – y) = ?

z(2x + y)/(2xz – y) = ?

Statement One Alone:

2x + y = 3

Although statement one provides a value for 2x + y, we still do not have a value for z or 2xz –y. Thus, statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

z = 2

Although statement two provides a value for z, we still do not have a value for 2xz – y or 2x + y. Thus, statement two alone is not sufficient to answer the question. We can eliminate answer choice B.

Statements One and Two Together:

Using statements one and two, we have values for z and 2x + y. However, since we still do not have a value for 2xz - y, we do not have enough information to answer the question.

Answer: E


Hi Jeff,

I understand that statement 1 & 2 alone are not sufficient but I opted for C in this way

From statement 2 we get z=2
denominator becomes 4x-y
=> 2x^2 -1y^2
=> (2x+y) (2x-y)



Thanks in advance!


Hi

The highlighted part. I think what you have done here is not correct. 4x - y cannot be written as (2x)^2 - y^2
Instead 4x = (2√x)^2 and y = (√y)^2, so we can write 4x - y as (2√x + √y)(2√x - √y)

So the answer will be E only
Re: If y ≠2xz, what is the value of (2xz + yz)/(2xz – y)?   [#permalink] 21 Jan 2018, 22:30
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