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In the figure above, if PQRS is a parallelogram, then y - x

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In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 15 Oct 2012, 04:25
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 15 Oct 2012, 04:25
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In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

In parallelogram corresponding angles are equal and consecutive angles are supplementary (supplementary angles are two angles that add up to 180°), thus:

\(140=2y\) --> \(y=70\);
\(2y+x=180\) --> \(140+x=180\) --> \(x=40\);

Therefore, \(y-x=70-40=30\).

Answer: A.

For more check Polygons chapter of Math Book: math-polygons-87336.html
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 15 Oct 2012, 04:34
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[quote="Bunuel"]The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Attachment:
PQRS.png
In the figure above, if PQRS is a parallelogram, then y - x =
(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

Note:- 1) Any two continuous interior angles of a parallelogram are supplementary.
2) Opposite angles are equal.

x= 180 - 140 = 40
x+2y = 180---> 2y = 180- x -----> 2y = 180- 40---->
y = 70

Thus y - x = 70 - 40 = 30
Answer A
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 15 Oct 2012, 11:08
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In the figure shown, angle x= QRS = QPS (opposite angles in parallelogram)
Also, intersecting lines PQ and PS, therefore QPS +Outerangle = 180
=> QPS =180-140 = 40
hence x =40

Also, Lines PQ and RS are parallel so angles they make with horizontal line PS are same. hence 2y =140
=> y =70

Therefore, y-x =70-40 = 30

Ans A.

Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Attachment:
PQRS.png
In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

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Question: 62
Page: 160
Difficulty: 650


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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 16 Oct 2012, 03:30
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since opposite sides and angles in a parallelogram are equal we know that

angle QRS = QPS = X
angle RSP = RPQ = 2y

140 + angle QPS = 180 ( sum of 2 angles on a straight line)

so X=40

now 2 ways to proceed sum of angles in parellogram is 360

so we have 2X+4Y=360
4Y = 360-80 ( 40*2)
4Y=280
Y=70 therefore Y-X=70-40 = 30 Answer Choice A

The other way since opposite sides are parallel PQ ll RS
hence 2Y=140 >>> y=70 and then Y-x = 70-40 = 30

In both cases Answer Choice is A
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 19 Oct 2012, 04:21
Image
In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

In parallelogram corresponding angles are equal and consecutive angles are supplementary (supplementary angles are two angles that add up to 180°), thus:

\(140=2y\) --> \(y=70\);
\(2y+x=180\) --> \(140+x=180\) --> \(x=40\);

Therefore, \(y-x=70-40=30\).

Answer: A.

For more check Polygons chapter of Math Book: math-polygons-87336.html

Kudos points given to everyone with correct solution. Let me know if I missed someone.
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 02 May 2013, 10:59
180-140= 40, x=40
140/2y= 70=y
y-x =
70-40=30
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 03 Jun 2016, 06:41
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Bunuel wrote:
Attachment:
PQRS.png
In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100


To solve we need to review some rules about parallelograms.

In parallelograms there are two main rules about the relationships between the angles:

1) Opposite angles are equal

Thus, angle P = angle R, and Angle Q = Angle S.

2) Consecutive angles are supplementary. That is, they add to 180 degrees.

Thus, angles Q and P add up to 180 degrees, as do angles P and S, angles S and R, and angles R and Q.

These rules can be used to solve the problem at hand.

We start by determining the value for angle P. We see that angle P is part of a straight angle. Since the exterior angle of angle P = 140 degrees, angle P must equal 40 degrees (since the two angles must sum to 180 degrees).

Using our first rule of parallelograms we see that angle R, which is equal to x, must also measure 40 degrees, since angles P and R are opposite angles.

Using our second rule of parallelograms, we know that angles R and S must add up to 180 degrees because they are consecutive angles. We note that angle S is equal to 2y. Thus:

2y + x = 180

2y + 40 = 180

2y = 140

y = 70

Therefore, the value of y – x is 70 – 40 = 30.

The answer is A.
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 05 Jul 2017, 21:27
Answer is A
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In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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New post 13 Sep 2017, 11:11
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Bunuel wrote:
Attachment:
PQRS.png
In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100


There are several ways to solve this question.
Here's one approach;

Since the two highlighted angles below share the same line, they must add to 180°
Image

So, ∠QPS = 40°
Image

Next, since the PQ||RS, we know that the two circled angles are corresponding angles, which means those two angles are equal
Image
If 2y° = 140°, then we know that y = 70°

Finally, since the two angles (circled in blue below) are opposite angles in a parallelogram, we know that they are EQUAL.
Image
So, x = 40°

This means y - x = 70 - 40 = 30

Answer: A

Cheers,
Brent
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Re: In the figure above, if PQRS is a parallelogram, then y - x  [#permalink]

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Re: In the figure above, if PQRS is a parallelogram, then y - x   [#permalink] 20 Dec 2018, 22:04
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