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In the figure above, the area of triangular region PQR is 36.What is

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Math Expert
Joined: 02 Sep 2009
Posts: 54376
In the figure above, the area of triangular region PQR is 36.What is  [#permalink]

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06 Sep 2017, 04:37
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15% (low)

Question Stats:

87% (01:13) correct 13% (02:56) wrong based on 39 sessions

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In the figure above, the area of triangular region PQR is 36.What is the area of the triangular region SQR?

(A) 12
(B) 16
(C) 24
(D) 30
(E) 36

Attachment:

2017-09-06_1535.png [ 7.32 KiB | Viewed 851 times ]

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Re: In the figure above, the area of triangular region PQR is 36.What is  [#permalink]

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06 Sep 2017, 05:00
Given figure triangle QPS is right triangle
so base PS = root(PS^2-PQ^2) = root(5^2-4^2)=3
Area PQS = 1/2 *4*3 = 6

Given area of PQR=36

So area SQR =Area PQR- Area PQS = 36-6 = 30

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Re: In the figure above, the area of triangular region PQR is 36.What is  [#permalink]

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06 Sep 2017, 05:13
Quote:
Given figure triangle QPS is right triangle
so base PS = root(PS^2-PQ^2) = root(5^2-4^2)=3

You might also recognize that triangle QPS is a 3-4-5 right triangle to save some time.

I agree with D as the answer
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Joined: 02 Jul 2017
Posts: 294
Concentration: Entrepreneurship, Technology
GMAT 1: 730 Q50 V38
Re: In the figure above, the area of triangular region PQR is 36.What is  [#permalink]

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06 Sep 2017, 05:25
markr89 wrote:
Quote:
Given figure triangle QPS is right triangle
so base PS = root(PS^2-PQ^2) = root(5^2-4^2)=3

You might also recognize that triangle QPS is a 3-4-5 right triangle to save some time.

I agree with D as the answer

Yes. 3-4-5 is basic right triangle. I just wrote full procedure for the sake of detailed explanation.

When i personally solve the question, i dont do all these procedures.
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Re: In the figure above, the area of triangular region PQR is 36.What is  [#permalink]

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11 Sep 2017, 10:54
Bunuel wrote:

In the figure above, the area of triangular region PQR is 36.What is the area of the triangular region SQR?

(A) 12
(B) 16
(C) 24
(D) 30
(E) 36

Attachment:
2017-09-06_1535.png

We see that triangle PRS is a 3-4-5 right triangle. Thus, the area of triangle PQS is 4 x 3 x 1/2 = 6.

So, the area of triangle SQR is 36 - 6 = 30.

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Re: In the figure above, the area of triangular region PQR is 36.What is   [#permalink] 11 Sep 2017, 10:54
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