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Math Expert V
Joined: 02 Sep 2009
Posts: 57281
In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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Difficulty:   35% (medium)

Question Stats: 80% (02:03) correct 20% (02:00) wrong based on 41 sessions

### HideShow timer Statistics In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment: #GREpracticequestion In the figure above, the circle is centered at.png [ 16.34 KiB | Viewed 572 times ]

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VP  P
Joined: 03 Jun 2019
Posts: 1059
Location: India
In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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Bunuel wrote: In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8=8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png

Distance between P(0,16) & Q(-10,-8)
$$=\sqrt{(0+10)^2 + (16+8)^2} = 26$$

IMO E
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Originally posted by Kinshook on 22 Jul 2019, 02:41.
Last edited by Kinshook on 22 Jul 2019, 03:43, edited 1 time in total.
Math Expert V
Joined: 02 Sep 2009
Posts: 57281
Re: In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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Kinshook wrote:
Bunuel wrote: In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8=8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png

Question needs some modification.
Distance between P(0,-16) & Q(-10,8)
$$=\sqrt{(0+10)^2 + (-16-8)^2} = 26$$

IMO E

The question is correct. It asks the distance between P, which is NOT at (0, -16) and (-10, -8).
_________________
VP  P
Joined: 03 Jun 2019
Posts: 1059
Location: India
Re: In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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Bunuel wrote:
Kinshook wrote:
Bunuel wrote: In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8=8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png

Question needs some modification.
Distance between P(0,-16) & Q(-10,8)
$$=\sqrt{(0+10)^2 + (-16-8)^2} = 26$$

IMO E

The question is correct. It asks the distance between P, which is NOT at (0, -16) and (-10, -8).

OK
Noted
_________________
"Success is not final; failure is not fatal: It is the courage to continue that counts."

Please provide kudos if you like my post. Kudos encourage active discussions.

My GMAT Resources: -

Efficient Learning

Tele: +91-11-40396815
Mobile : +91-9910661622
E-mail : kinshook.chaturvedi@gmail.com
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 3018
In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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Solution

Given:
A circle with center at (0, 0)
One end-point of the diameter on y-axis as (0, - 16)

To find:
The distance between point P and the point (–10, –8)

Approach and Working Out:
Since, P is the other end point of the diameter on y-axis
The coordinates of point P are (0, 16)

Therefore, the distance between (0, 16) and (-10, -8) = $$√((0 – (-10))^2+ (16 – (-8))^2 ) = √(100 + 576)= √676= 26$$

Hence, the correct answer is Option E.

Answer: E

_________________ In the figure above, the circle is centered at (0, 0). What is the dis   [#permalink] 23 Jul 2019, 04:05
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