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In the figure above, the circle is centered at (0, 0). What is the dis

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In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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New post 22 Jul 2019, 01:16
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E

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  35% (medium)

Question Stats:

80% (02:03) correct 20% (02:00) wrong based on 41 sessions

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In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion  In the figure above, the circle is centered at.png
#GREpracticequestion In the figure above, the circle is centered at.png [ 16.34 KiB | Viewed 561 times ]

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In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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New post Updated on: 22 Jul 2019, 03:43
Bunuel wrote:
Image
In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8=8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png




Distance between P(0,16) & Q(-10,-8)
\(=\sqrt{(0+10)^2 + (16+8)^2} = 26\)


IMO E
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Originally posted by Kinshook on 22 Jul 2019, 02:41.
Last edited by Kinshook on 22 Jul 2019, 03:43, edited 1 time in total.
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Re: In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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New post 22 Jul 2019, 02:49
Kinshook wrote:
Bunuel wrote:
Image
In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8=8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png



Question needs some modification.
Distance between P(0,-16) & Q(-10,8)
\(=\sqrt{(0+10)^2 + (-16-8)^2} = 26\)


IMO E


The question is correct. It asks the distance between P, which is NOT at (0, -16) and (-10, -8).
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Re: In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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New post 22 Jul 2019, 03:44
Bunuel wrote:
Kinshook wrote:
Bunuel wrote:
Image
In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8=8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png



Question needs some modification.
Distance between P(0,-16) & Q(-10,8)
\(=\sqrt{(0+10)^2 + (-16-8)^2} = 26\)


IMO E


The question is correct. It asks the distance between P, which is NOT at (0, -16) and (-10, -8).



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In the figure above, the circle is centered at (0, 0). What is the dis  [#permalink]

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New post 23 Jul 2019, 04:05

Solution


Given:
    A circle with center at (0, 0)
    One end-point of the diameter on y-axis as (0, - 16)

To find:
    The distance between point P and the point (–10, –8)

Approach and Working Out:
    Since, P is the other end point of the diameter on y-axis
      The coordinates of point P are (0, 16)

    Therefore, the distance between (0, 16) and (-10, -8) = \(√((0 – (-10))^2+ (16 – (-8))^2 ) = √(100 + 576)= √676= 26\)

Hence, the correct answer is Option E.

Answer: E

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In the figure above, the circle is centered at (0, 0). What is the dis   [#permalink] 23 Jul 2019, 04:05
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