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Math Expert
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Math Expert
Joined: 02 Sep 2009
Posts: 92881
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Given Kudos: 81562
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GMAT Club Legend
GMAT Club Legend
Joined: 03 Jun 2019
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Own Kudos [?]: 3962 [0]
Given Kudos: 160
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
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Re: In the figure above, the circle is centered at (0, 0). What is the dis [#permalink]
Bunuel wrote:
Kinshook wrote:
Bunuel wrote:

In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8=8) (not shown on the graph)?

(A) 18

(B) 20

(C) 22

(D) 24

(E) 26

Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png



Question needs some modification.
Distance between P(0,-16) & Q(-10,8)
\(=\sqrt{(0+10)^2 + (-16-8)^2} = 26\)


IMO E


The question is correct. It asks the distance between P, which is NOT at (0, -16) and (-10, -8).



OK
Noted
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In the figure above, the circle is centered at (0, 0). What is the dis [#permalink]
Expert Reply

Solution


Given:
    A circle with center at (0, 0)
    One end-point of the diameter on y-axis as (0, - 16)

To find:
    The distance between point P and the point (–10, –8)

Approach and Working Out:
    Since, P is the other end point of the diameter on y-axis
      The coordinates of point P are (0, 16)

    Therefore, the distance between (0, 16) and (-10, -8) = \(√((0 – (-10))^2+ (16 – (-8))^2 ) = √(100 + 576)= √676= 26\)

Hence, the correct answer is Option E.

Answer: E

GMAT Club Bot
In the figure above, the circle is centered at (0, 0). What is the dis [#permalink]
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