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04 Oct 2018, 02:32
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (02:00) correct
19%
(02:45)
wrong
based on 103
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure shown below, what is the value of K?
(A) 45
(B) 50
(C) 55
(D) 65
(E) 70
2018-10-04_1331.png [ 32.23 KiB | Viewed 3248 times ]
(A) 45
(B) 50
(C) 55
(D) 65
(E) 70
Attachment:
2018-10-04_1331.png [ 32.23 KiB | Viewed 3248 times ]
04 Oct 2018, 02:50
Kudos
Bookmarks
Right Triangle PSR is a 5-12-13. Hence, PR=13
Right Triangle PQT= 84^2 + pq^2= 85^2 --- PQ^2=85^2-84^2
PQ^2= (85+84)(85-84)= 169
PQ=13
Hence, Triangle PQR is an isosceles triangle
since, PQ= 13 and opposite angle Q= 65degrees, similarly PR=13, hence, opposite angle R= 65degrees
180-(2*65)= 50
Ans= B
Right Triangle PQT= 84^2 + pq^2= 85^2 --- PQ^2=85^2-84^2
PQ^2= (85+84)(85-84)= 169
PQ=13
Hence, Triangle PQR is an isosceles triangle
since, PQ= 13 and opposite angle Q= 65degrees, similarly PR=13, hence, opposite angle R= 65degrees
180-(2*65)= 50
Ans= B
14 Dec 2020, 12:12
Kudos
Bookmarks
Bunuel
Triangle PSR support Pythagorean Triples \(5:12:13\)
\(PR=12,\) PR is also a side of Triangle \(PRQ.\)
Triangle PQT is also a right triangle, where: \(PQ^2+QT^2=PT^2\)
\(PQ^2+84^2=85^2\)
\(PQ^2+84^2=(84+1)^2\)
\(PQ^2=84^2+2*84*1+1^2-84^2\)
\(PQ^2=168+1=169\)
\(PQ=\sqrt{163}=13\), Which is a side of Triangle \(PRQ\)
In Triangle \(PRQ\), \(PR=PQ=13\)
So, Triangle \(PRQ \) is an isosceles triangle, Whose two angles 65 each, So, the other Angle \(X=180-(65+65)=50\)
The answer is B
