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Bunuel
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Total number of students = 50
number of boys = 90 % of 50 = 45
number of girls = 10 % of 50 = 5
now the number of girls remains the same i.e. 5
but this number should be 5 % of a new number of students
5% of x = 5 where x is new total of students
x= 100
so 50 students are added but we know that we can't change number of girls so number of boys is thus increased by 50
correct answer - A
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Bunuel
In the Hillside summer camp there are 50 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen?

A. 50.
B. 45.
C. 40.
D. 30.
E. 25.
Algebraically:

\(.05=\frac{5}{(50+x)}\)
\(x=5\)
\(45+5 = 50\)
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Percent =Change/Original *100

Change of girls to 5%
Original=10 %

Total increase =5/10*100 =50
Hence A
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Bunuel
In the Hillside summer camp there are 50 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen?

A. 50.
B. 45.
C. 40.
D. 30.
E. 25.

currently X = 50

M = 45 (90%) W = 5 (10%)

So we have to add men, which means women count is constant

we have currently 5 women. we make it a 5 %

(5/100) * X = 5

So X =100

we now have X=50 , so we have add another 50 male to make it as 100.

So Ans is A
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Total = 50 children
0.9 x 50 = 45 Boys , 5 Girls
To make 95% Boys and 5% Girls
Add 50 Boys + 45 Boys + 5 girls = 100 Children
5 girls = 5% of 100
A
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