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  • Typical Day of a UCLA MBA Student - Recording of Webinar with UCLA Adcom and Student

     December 14, 2018

     December 14, 2018

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    Carolyn and Brett - nicely explained what is the typical day of a UCLA student. I am posting below recording of the webinar for those who could't attend this session.
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    Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

In the xy-plane, line L has equation y=mx+b, where 1<m<5. If line L

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In the xy-plane, line L has equation y=mx+b, where 1<m<5. If line L  [#permalink]

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New post 04 Jul 2018, 00:54
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

67% (02:05) correct 33% (02:23) wrong based on 46 sessions

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[GMAT math practice question]

In the xy-plane, line L has equation \(y=mx+b\), where \(1<m<5\). If line L passes through (1,1), which of the following points also lies on line L?

A. (2, -1)
B. (2,0)
C. (2,1)
D. (2,2)
E. (2,3)

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Re: In the xy-plane, line L has equation y=mx+b, where 1<m<5. If line L  [#permalink]

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New post 04 Jul 2018, 01:24
MathRevolution wrote:
[GMAT math practice question]

In the xy-plane, line L has equation \(y=mx+b\), where \(1<m<5\). If line L passes through (1,1), which of the following points also lies on line L?

A. (2, -1)
B. (2,0)
C. (2,1)
D. (2,2)
E. (2,3)


Use equation to solve..
\(y=mx+b............1=m+b........ b=1-m.\)
Since b is constant, y=mx+b=mx+1-m

Now all choices contain x as 2, substitute y=2m+1-m=m+1

Now 1<m<5 ....... Add 1 to all
1+1<m+1<5+1......2<m+1<6
In all choices Only value given is 3
So ans (2,3)

E
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Re: In the xy-plane, line L has equation y=mx+b, where 1<m<5. If line L  [#permalink]

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New post 04 Jul 2018, 01:49
MathRevolution wrote:
[GMAT math practice question]

In the xy-plane, line L has equation \(y=mx+b\), where \(1<m<5\). If line L passes through (1,1), which of the following points also lies on line L?

A. (2, -1)
B. (2,0)
C. (2,1)
D. (2,2)
E. (2,3)


\(y=mx + b\) 1

(1,1) is a point on the line

Substitute \(X=1\) and \(Y=1\)
We get \(m=-b\) 2

Substitute 2 in 1

\(y=-bx+b\)
Options A, B, C can be eliminated because value of B will be less than 1 and this the value of M would not meet the criteria mentioned in the question.

Options D and E would fit the criteria, however, Option D can be eliminated because if (2,2) is a point and (1,1) is a point on the line, then the slope, m, would be equal to 1. But \(1<m<5\).
Therefore, Option E.
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Re: In the xy-plane, line L has equation y=mx+b, where 1<m<5. If line L  [#permalink]

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New post 06 Jul 2018, 00:44
=>

When we plug in the values \(x = 1\) and \(y = 1\), we obtain \(1 = m + b\) or \(b = 1 – m\).
All answer choices have x-coordinates of 2. Plugging 2 in for the variable \(x\) yields
\(y = 2m + b = 2m + 1 – m = m + 1.\)
Since \(1 < m < 5\), we must have \(2 < m + 1 < 6\) and \(2 < y < 6.\)
Thus, \((2,3)\) is the only point that can lie on the line.

Therefore, the answer is E.
Answer: E
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Re: In the xy-plane, line L has equation y=mx+b, where 1<m<5. If line L &nbs [#permalink] 06 Jul 2018, 00:44
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