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# In triangle ABC, AB=BC and (C's measure is 65°. ) What is the measure

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Math Expert
Joined: 02 Sep 2009
Posts: 64242
In triangle ABC, AB=BC and (C's measure is 65°. ) What is the measure  [#permalink]

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08 Aug 2019, 00:33
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25% (medium)

Question Stats:

73% (00:37) correct 27% (00:26) wrong based on 43 sessions

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In triangle ABC, AB=BC and C's measure is 65°. What is the measure of angle B?

A. 40°
B. 50°
C. 60°
D. 65°
E. 75°

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CEO
Joined: 03 Jun 2019
Posts: 2931
Location: India
GMAT 1: 690 Q50 V34
WE: Engineering (Transportation)
Re: In triangle ABC, AB=BC and (C's measure is 65°. ) What is the measure  [#permalink]

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08 Aug 2019, 02:48
Bunuel wrote:
In triangle ABC, AB=BC and C's measure is 65°. What is the measure of angle B?

A. 40°
B. 50°
C. 60°
D. 65°
E. 75°

Given: In triangle ABC, AB=BC and C's measure is 65°.

Asked: What is the measure of angle B?

AB=BC => Angle A = Angle C = 65°
For a triangle, sum of all 3 angles = 180°
2*65+B = 180
B=50°

IMO B
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Kinshook Chaturvedi
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Joined: 07 Mar 2019
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GMAT 1: 580 Q43 V27
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Re: In triangle ABC, AB=BC and (C's measure is 65°. ) What is the measure  [#permalink]

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08 Aug 2019, 03:40
Bunuel wrote:
In triangle ABC, AB=BC and C's measure is 65°. What is the measure of angle B?

A. 40°
B. 50°
C. 60°
D. 65°
E. 75°

Since the triangle is an isosceles triangle(AB = BC). Angles opposite to sides AB(∠C) and BC(∠A) would also be equal. We need to find ∠B.
As, ∠C = 65⁰
 ∠B = 65⁰

We know sum of all the angles of a triangle = 180⁰
 ∠A + ∠B + ∠C = 180⁰
 ∠B = 180⁰ - (∠A + ∠C)
 ∠B = 180⁰ - (65⁰ + 65⁰)
 ∠B = 180⁰ - 130⁰
 ∠B = 50⁰

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Re: In triangle ABC, AB=BC and (C's measure is 65°. ) What is the measure   [#permalink] 08 Aug 2019, 03:40