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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
72% (01:38) correct
28%
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Is \(\frac{7^{(x+2)}}{49} > 1\) ?
(1) \(7^{(x - 2)} > \frac{1}{49}\)
(2) \(7^{(x - 1)} > \frac{1}{49}\)
(1) \(7^{(x - 2)} > \frac{1}{49}\)
(2) \(7^{(x - 1)} > \frac{1}{49}\)
16 Dec 2017, 06:05
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Bunuel
Is \(\frac{7^{(x+2)}}{49} > 1\) ?
(1) \(7^{(x - 2)} > \frac{1}{49}\)
(2) \(7^{(x - 1)} > \frac{1}{49}\)
(1) \(7^{(x - 2)} > \frac{1}{49}\)
(2) \(7^{(x - 1)} > \frac{1}{49}\)
Slightly tricky q..
\(\frac{7^{(x+2)}}{49} > 1..........7^x>1\) MEANS --- Is x>0?
lets see the statements
(1) \(7^{(x - 2)} > \frac{1}{49}...........7^{(x-2+2)}>1...........7^x>1\)
Sufficient
(2) \(7^{(x - 1)} > \frac{1}{49}...........7^{(x-1+2)}>1.......7^{(x+1)}>0\)
so x+1>0....x>-1
if x is between -1 and 0 , ans is NO
otherwise Yes
insuff
A
16 Dec 2017, 09:10
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Bunuel
Is \(\frac{7^{(x+2)}}{49} > 1\) ?
(1) \(7^{(x - 2)} > \frac{1}{49}\)
(2) \(7^{(x - 1)} > \frac{1}{49}\)
(1) \(7^{(x - 2)} > \frac{1}{49}\)
(2) \(7^{(x - 1)} > \frac{1}{49}\)
Simplify: \(\frac{7^{(x+2)}}{49} > 1 = \frac{7^{(x+2)}}{(7^2)} > 1 =7^{(x+2)-2}> 1.\)
Question: Is \(x > 0?\)
(1) \(7^{(x - 2)} > \frac{1}{49} = 7^{(x - 2)} > \frac{1}{7^2} = 7^{(x - 2)} > 7^{(-2)} = x-2>-2 = x > 0.\) Sufficient.
(2) \(7^{(x - 1)} > \frac{1}{49} = 7^{(x - 1)} > \frac{1}{7^2} = 7^{(x - 1)} > 7^{(-2)} = x-1>-2 = x-1+2 > 0 = x > -1.\) Insufficient.
(A) is the answer.
