pingala wrote:
I messed up on how i interpreted statement two, the fact that
x=y=1 would create the right condition for statement 2 to be correct, also means that when answering the prompt,
x>y, we get the answer
NO; trying another set of numbers- x=2 and y=1- where statement two meets the condition,
2>1/3, means that the answer to the question
x>y is
YES.
Bunuel explains this but I didn't quite understand the process because I wasn't registering the prompt and statement criteria clearly.
Hi
pingala,
here is how i would approach this question
we are asked that IS x>y
so is x-y>0
what could be the possible senarios
x>0, y>0 and |x|>|y|
x<0, y<0 and |y|>|x|
x>0, y<0
x<0, y>0 and |y|>|x|
in above all scenarios we would get the answer to our question.
Now statement A:
It says y>0. It could be x>0 or x<0, but still we don't about |x| and |y|
So insufficient.
Now Statement B:
3x>2y
or we can have
\(x>\frac{2}{3} y\)
if we read along it says x is greater than two-thirds of y.
We will have two senarios
y>0 even then we can't conclude that x> y. why say y>1 then x can be \(>\frac{2}{3}\) . So its possible that the range of of x is \(\frac{2}{3}<x<\infty\) and range of y would be \(1<y< \infty\) . Now if you imagine a number line with these two ranges then you can either conclude that x<y or x>y
Now if y<0 even then we can't conclude that x> y. Then x can be \(>-\frac{2}{3}\) . So its possible that the range of of x is \(-\frac{2}{3}<x<\infty\) and range of y would be \(-\infty<y<0\). Now if you imagine a number line with these two ranges then you can either conclude that x<y or x>y
Now even if we combine both the statements still we don't have any new information to conclusively answer if x>y
hence option E
let me know if this helps
Probus
_________________
Probus
~You Just Can't beat the person who never gives up~ Babe Ruth