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Is x + y > 1?
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Updated on: 26 Oct 2017, 03:07
Question Stats:
35% (02:14) correct 65% (02:01) wrong based on 77 sessions
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Is x + y > 1? (1) x^2  y^2 > 1 (2) x/y + 1 > 0, where y is positive.
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Originally posted by AsadAbu on 09 Apr 2016, 14:31.
Last edited by chetan2u on 26 Oct 2017, 03:07, edited 3 times in total.
Corrected the OA



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Re: Is x + y > 1?
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09 Apr 2016, 19:54
iMyself wrote: is x+y>1?
1) x^2y^2>1 2) x/y+1>0, where y is positive. Hi, lets see the statements 1) \(x^2y^2>1\)OR (xy)(x+y)>1.. Insuff 2) \(\frac{x}{y}+1>0\), where y is positive(x+y)/y>0 since y is positive, x+y is also positive.. but we cannot say if x+y>1 insuff combined..x+y is positive , so xy is also +ive.. which means x>y..Now \(x^2y^2>1....x^2>1+y^2\) so so \(x^2>1\) and as x is POSITIVE, x>1 so x+y will be >1 sufficient C
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Re: Is x + y > 1?
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09 Apr 2016, 22:38
Thanks chetan2u. So, what will be the difficulty level of this question?
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Re: Is x + y > 1?
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09 Apr 2016, 22:41
iMyself wrote: Thanks chetan2u. So, what will be the difficulty level of this question? hi, It should be close to 600650 since it contains two variables and inequality too..
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: Is x + y > 1?
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09 Apr 2016, 22:47
chetan2u wrote: iMyself wrote: Thanks chetan2u. So, what will be the difficulty level of this question? hi, It should be close to 600650 since it contains two variables and inequality too.. how can we be sure that it is close to 600650 by seeing ''since it contains two variables and inequality too''. I want to know just for curiosity.
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Re: Is x + y > 1?
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09 Apr 2016, 23:59
iMyself wrote: chetan2u wrote: iMyself wrote: Thanks chetan2u. So, what will be the difficulty level of this question? hi, It should be close to 600650 since it contains two variables and inequality too.. how can we be sure that it is close to 600650 by seeing ''since it contains two variables and inequality too''. I want to know just for curiosity. Personal Opinion => This is a 650  700 level.. Again => This is a personal opinion ..
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Re: Is x + y > 1?
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10 Apr 2016, 00:26
iMyself wrote: chetan2u wrote: iMyself wrote: Thanks chetan2u. So, what will be the difficulty level of this question? hi, It should be close to 600650 since it contains two variables and inequality too.. how can we be sure that it is close to 600650 by seeing ''since it contains two variables and inequality too''. I want to know just for curiosity. Hi, generally inequalities and two variables Q are considered to be difficult by any average person, BUT since the Q has some straight forward equations, it can be 600650 level.. However difficulty level is each ones perception. A difficult topic such as prob may be easy for you but very difficult for others
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: Is x + y > 1?
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Updated on: 10 Apr 2016, 06:56
Thanks @chetan2u. I got it
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Originally posted by AsadAbu on 10 Apr 2016, 00:42.
Last edited by AsadAbu on 10 Apr 2016, 06:56, edited 1 time in total.



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Re: Is x + y > 1?
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10 Apr 2016, 11:05
GMAT is nothing but all about technique. So could you please give a technique of this problem? Can you share unconventional method/shortcut way for THIS problem? Thanks...
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Is x + y > 1?
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Updated on: 26 Oct 2017, 04:33
chetan2u wrote: Hi, I think you are subconsciously taking x and y as integers.. but say if x and y are fractions.. x= 1/2 and y = 1/4 .. x+ y <1.. But x= 1/2 and y = 1/4 > x^2  y^2 < 1 > statement 1 is not satisfied. Hi Bunuel! From (1) and (2), we have y > 0, x + y > 0 and x  y > 0 (Or x > y). Assume x + y <= 1 > x  y <= x + y <= 1 > x^2  y^2 = (xy)(x+y) <= 1 > contradict the statement (1) > x + y> 1 > C I think the OA must be C, please confirm! Many thanks ^^
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Originally posted by leanhdung on 26 Oct 2017, 02:44.
Last edited by leanhdung on 26 Oct 2017, 04:33, edited 1 time in total.



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Re: Is x + y > 1?
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26 Oct 2017, 03:05
leanhdung wrote: chetan2u wrote: Hi, I think you are subconsciously taking x and y as integers.. but say if x and y are fractions.. x= 1/2 and y = 1/4 .. x+ y <1.. But x= 1/2 and y = 1/4 > x^2  y^2 < 1 > statement 1 is not satisfied. Hi Bunuel! From (1) and (2), we have y > 0, x + y > 0 and x  y > 0 (Or x > y). Assume x + y <= 1 > x  y <= x + y <= 1 > x^2  y^2 = (xy)(x+y) <= 1 > contradict the statement (1) > x^2  y^2> 1 > C I think the OA must be C, please confirm! Many thanks ^^ Hi.. You are absolutely correct OA has to be C.. editing the OA +1 kudos
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: Is x + y > 1? &nbs
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