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Kinshook's quant questions

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Kinshook's quant questions  [#permalink]

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New post Updated on: 21 Aug 2019, 08:01
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Kinshook's Quant Questions

This topic is created to segregate quant questions created by me from general pool of quant questions in GMATClub forums.
Presently there is no specific frequency of posting questions but approx 1 question in every 3 days is what I am planning to do.

Hope you enjoy my questions.

Regards
Kinshook
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Originally posted by Kinshook on 19 Aug 2019, 03:00.
Last edited by Kinshook on 21 Aug 2019, 08:01, edited 2 times in total.
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Re: Kinshook's quant questions  [#permalink]

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New post Updated on: 21 Aug 2019, 08:00
What is maximum power of 111 that divides 30!*31!*32!*33!*34!*35!*36!*37!*38!*39!*40!?

A. 3
B. 4
C. 5
D. 6
E. 11

Spoiler: :: OA
B

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Originally posted by Kinshook on 19 Aug 2019, 03:52.
Last edited by Kinshook on 21 Aug 2019, 08:00, edited 4 times in total.
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Re: Kinshook's quant questions  [#permalink]

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New post 19 Aug 2019, 04:09
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111=3*37, 37 is a prime number so we need to check how many times can 37 can divide 30! * 31! * 32! * 33! * 34! * 35! * 36! * 37! * 38! * 39! * 40!. Therefore 4 times (B)

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Re: Kinshook's quant questions  [#permalink]

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New post 20 Aug 2019, 00:18
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When you see a question like this related to factorials and highest powers, know that the expression containing the factorial always represents the dividend AND the number for which you are trying to find the highest power, always represents the divisor.

Therefore, the idea is to work on breaking down the divisor into its prime factors (if it is not a prime number already).

In this question, therefore, the huge expression, 30! * 31! * 32!*….. is the dividend and the number 111 is the divisor.

111 = 37 * 3.

Finding the highest power of 111 which divides the 30!*31!*32!*…. is equivalent to finding the highest power of 37 and 3 that is contained in the expression.

The bigger number of the two is 37. Clearly, the highest power of this number will be much lesser than the highest power of 3, because there are going to be far fewer number of 37s in the product than the number of 3s.

So, finding the highest power of 111 is essentially the same as finding the highest power of 37.

30! * 31! * 32! * 33! * 34! * 35! * 36! * 37!* 38!* 39! * 40! – in this expression, as we see, 37 comes up exactly 4 times i.e. in 37!, 38!, 39! and 40!
The highest power of 37, and hence 111, is 4.

The correct answer option is B.

Hope this helps!
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New post 23 Aug 2019, 08:31
What is the sum of all roots of the equation \((x^2 - 4x -9)( 2x^2 + 8x - 11)=0\)?

A. 0
B. -4
C. 99
D. 4
E. 8

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Spoiler: :: OA
A

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Please provide kudos if you like my post. Kudos encourage active discussions.

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E-mail : kinshook.chaturvedi@gmail.com
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Re: Kinshook's quant questions  [#permalink]

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New post 24 Aug 2019, 07:42
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Kinshook wrote:
What is the sum of all roots of the equation \((x^2 - 4x -9)( 2x^2 + 8x - 11)=0\)?

A. 0
B. -4
C. 99
D. 4
E. 8


Sum of all roots:
1) x^2 - 4x -9 =0
x1 + x2 = -(-4) = 4

2) 2x^2 + 8x - 11=0
x3 + x4 = -(8/2) = -4

x1+ x2 + x3 + x4 = 4 + (-4) = 0
Answer is (A)

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Re: Kinshook's quant questions   [#permalink] 24 Aug 2019, 07:42
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