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Updated on: 06 Jul 2019, 01:04
Originally posted by Bunuel on 19 Jun 2017, 00:23.
Last edited by Sajjad1994 on 06 Jul 2019, 01:04, edited 1 time in total.
Last edited by Sajjad1994 on 06 Jul 2019, 01:04, edited 1 time in total.
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E
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Let A denote the area of a circular region. Which of the following denotes the circumference of that circular region?
(A) \(\sqrt{\frac{A}{\pi}}\)
(B) \(2\frac{A}{\sqrt{\pi}}\)
(C) \(2\pi \sqrt{A}\)
(D) \(2\sqrt{\frac{A}{\pi}}\)
(E) \(2\pi \sqrt{\frac{A}{\pi}}\)
(A) \(\sqrt{\frac{A}{\pi}}\)
(B) \(2\frac{A}{\sqrt{\pi}}\)
(C) \(2\pi \sqrt{A}\)
(D) \(2\sqrt{\frac{A}{\pi}}\)
(E) \(2\pi \sqrt{\frac{A}{\pi}}\)
Source: Nova GMAT
Difficulty Level: 550
Difficulty Level: 550
19 Jun 2017, 00:30
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Let radius of the circle = r
Area of circle = \(\pi\)\(r^2\)
Circumference of circle = 2\(\pi\)r
Now given
Area of circle = A
A = \(\pi\)\(r^2\)
r =\(\sqrt{A/\pi}\)
Circumference = 2\(\pi\)\(\sqrt{A/\pi}\)
Answer is E
Area of circle = \(\pi\)\(r^2\)
Circumference of circle = 2\(\pi\)r
Now given
Area of circle = A
A = \(\pi\)\(r^2\)
r =\(\sqrt{A/\pi}\)
Circumference = 2\(\pi\)\(\sqrt{A/\pi}\)
Answer is E
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Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
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19 Jun 2017, 00:58
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Bunuel
Let A denote the area of a circular region. Which of the following denotes the circumference of that circular region?
(A) \(\sqrt{\frac{A}{\pi}}\)
(B) \(2\frac{A}{\sqrt{\pi}}\)
(C) \(2\pi \sqrt{A}\)
(D) \(2\sqrt{\frac{A}{\pi}}\)
(E) \(2\pi \sqrt{\frac{A}{\pi}}\)
(A) \(\sqrt{\frac{A}{\pi}}\)
(B) \(2\frac{A}{\sqrt{\pi}}\)
(C) \(2\pi \sqrt{A}\)
(D) \(2\sqrt{\frac{A}{\pi}}\)
(E) \(2\pi \sqrt{\frac{A}{\pi}}\)
Let the radius of circular region be \(= r\)
Area of circular region, \(A =\) \(\pi\)\(r^2\)
\(r^2\) \(= \frac{A}{\pi}\)
\(r =\sqrt{\frac{A}{\pi}}\) ------------- (i)
Circumference of circular region, \(C = 2\)\(\pi\)\(r\) ------------ (ii)
Substituting value of \(r\) from (i) in (ii), we get;
\(C = 2\pi\sqrt{\frac{A}{\pi}}\) . Answer (E)...
