aimtoteach
Bunuel
Official Solution:
(1) The product of any three integers in the set is negative. If the set consists of only 3 terms, then the set could be either {negative, negative, negative} or {negative, positive, positive}. If the set consists of more than 3 terms, then the set can only have negative numbers. Not sufficient.
(2) The product of the smallest and largest integers in the set is a prime number. Since only positive numbers can be primes, then the smallest and largest integers in the set must be of the same sign. Thus the set consists of only negative or only positive integers. Not sufficient.
(1)+(2) Since the second statement rules out {negative, positive, positive} case which we had from (1), then we have that the set must have only negative integers. Sufficient.
Answer: C
Hello!
I didnt get this one. What if the set has 4 values - 2 positive and 2 negative.
-> [2,3,-1,-5]
Now if we pick any 3 values it can be either positive or negative. e.g 2*3*-1 = -6 but -5*-1*2 - 10
Can you please explain.
Thanks!
Hi,
It seems you are trying to falsify what is already established in the statement. Statement A states that product of ANY three nos. is negative. Hence we take only those sets of nos. where this condition holds true.
Statement A states that the product of ANY 3 nos. in the set is negative. This can only be true when all the nos. are negative or one or two nos. are positive based on the size of the set. (if it is a three no. set, then two positive nos., for more than 3 no. sets, 1 positive no.) {simply because if there are 3 positive nos., it will hold the Statement A false}. As nos. can be either positive(one or two) or negative, Hence A is not sufficient.
And B states that the product of min and max value is prime. Since only positive nos. can be prime, min and max values should both be either positive or negative. Again B is not sufficient
Thus taking A & C together, both min and max can not be positive since A has already established that all the nos. can not be positive (if min and max are both positive this means all the nos., lie between min and max, will also be positive)
Thus if min and max are both negative, all the nos. are negative which back the inference we made in A.
Hence C is the answer.