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Math Expert V
Joined: 02 Sep 2009
Posts: 59622

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Difficulty:   5% (low)

Question Stats: 94% (01:24) correct 6% (02:36) wrong based on 32 sessions

### HideShow timer Statistics Seven cookies of radius 1 inch are cut from a circle of cookie dough, as shown. Neighboring cookies are tangent, and all except the center cookie are tangent to the edge of the dough. The leftover scrap is reshaped to form another cookie of the same thickness. What is the radius in inches of the scrap cookie?

(A) $$\sqrt{2}$$
(B) 1.5
(C) $$\sqrt{\pi}$$
(D) $$\sqrt{2\pi}$$
(E) $$\pi$$

Attachment: cca00f7535d16d5f82c2832dbebe7bf865368fed.png [ 24.84 KiB | Viewed 414 times ]

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Intern  B
Joined: 24 Apr 2019
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Area of outer circle=$$pi*3^2=9pi$$
Area of 7 cookies=$$7*pi*1^2=7pi$$

Area of left over=$$2pi$$
Radius=$$\sqrt{2}$$
IMo, Option A.
Senior Manager  P
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GMAT 1: 580 Q47 V23 GMAT 2: 640 Q49 V27 GPA: 4
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Each cookie area is $$\pi$$

The larger circle area is $$9\pi$$ (radius of the larger circle is 3)

Area of 7 cookies is $$7\pi$$

Scrap area is $$9\pi - 7\pi$$

$$2\pi$$

$$\pi*r^2 = 2\pi$$

$$r = \sqrt{2}$$

OPTION: A
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The radius of the entire cookie dough is 3 in. => Area of the entire dough is (pie)(r^2)

Subtracting, we get left over area as 2*(pie) = (pie)*(r^2)

=> r = root2

~ I'm not used to the using math in text ~ Display posts from previous: Sort by  