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# The figure above is a rectangular solid with AB = 10, BC = 10, and CD

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Math Expert
Joined: 02 Sep 2009
Posts: 61302
The figure above is a rectangular solid with AB = 10, BC = 10, and CD  [#permalink]

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30 Oct 2019, 22:54
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Difficulty:

15% (low)

Question Stats:

90% (00:55) correct 10% (00:38) wrong based on 39 sessions

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The figure above is a rectangular solid with AB = 10, BC = 10, and CD = 3. What is the total surface area of the figure?

(A) 320
(B) 300
(C) 220
(D) 160
(E) 23

Attachment:

2017-12-01_0946.png [ 4.92 KiB | Viewed 507 times ]

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Re: The figure above is a rectangular solid with AB = 10, BC = 10, and CD  [#permalink]

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31 Oct 2019, 04:28
The figure above is a rectangular solid with L = 10, B = 10, and H = 3. What is the total surface area of the figure?

the formula for the total surface area of a rectangular solid is given by 2(LB+BH+LH)

2(10*10+ 10*3+ 10*3)

2(100+30+30)

=>160*2=320

option A is correct
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Re: The figure above is a rectangular solid with AB = 10, BC = 10, and CD  [#permalink]

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24 Jan 2020, 05:13
Bunuel wrote:

The figure above is a rectangular solid with AB = 10, BC = 10, and CD = 3. What is the total surface area of the figure?

(A) 320
(B) 300
(C) 220
(D) 160
(E) 23

Attachment:
2017-12-01_0946.png

2*100+2*30+2*30=200+60+60=320
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Re: The figure above is a rectangular solid with AB = 10, BC = 10, and CD  [#permalink]

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24 Jan 2020, 06:50
Bunuel wrote:

The figure above is a rectangular solid with AB = 10, BC = 10, and CD = 3. What is the total surface area of the figure?

(A) 320
(B) 300
(C) 220
(D) 160
(E) 23

Attachment:
2017-12-01_0946.png

$$2(10*10 + 10*3+ 10*3)$$

$$= 2(100 + 30 + 30)$$

$$= 320$$, Answer must be (A)
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Re: The figure above is a rectangular solid with AB = 10, BC = 10, and CD   [#permalink] 24 Jan 2020, 06:50
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