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13 Jul 2018, 00:11
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Difficulty:
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Question Stats:
73% (01:15) correct
27%
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The measures of two angles of a parallelogram differ by 52 degrees. The number of degrees in the smaller angle is
(A) 38
(B) 52
(C) 64
(D) 76
(E) 128
(A) 38
(B) 52
(C) 64
(D) 76
(E) 128
13 Jul 2018, 00:21
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Bunuel
The measures of two angles of a parallelogram differ by 52 degrees. The number of degrees in the smaller angle is
(A) 38
(B) 52
(C) 64
(D) 76
(E) 128
(A) 38
(B) 52
(C) 64
(D) 76
(E) 128
Let x and y are the measure two adjacent angles of the parallelogram, So the measure of the 4 angles of parallelogram are x,y,x, and y in cyclic order.
Given x-y=52 degree----(1)
We know, sum of adjacent angles in a parallelogram is 180.
So, x+y=180.------(2)
Solving (1) & (2) , we have
x=116 degree & y=64 degree.
So, the measure of smallest angle is 64 degree.
Ans. (C)
13 Jul 2018, 00:21
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Bunuel
The measures of two angles of a parallelogram differ by 52 degrees. The number of degrees in the smaller angle is
(A) 38
(B) 52
(C) 64
(D) 76
(E) 128
(A) 38
(B) 52
(C) 64
(D) 76
(E) 128
Let, the angles be a and b
a + a+ b+ b = 360
a + b = 180 --> (1)
Given,
a - b = 52 --> (2)
Solving (1) and (2), we get a = 116 (larger)
b = 64 (smaller)
Hence, C.
