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(0.04×0.04×0.04)/(0.08×0.08×0.08×0.08)

1/(8×0.08)

100/64

25/16

C

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Bunuel
\(\frac{(0.08)^{(–4)}}{(0.04)^{(–3)}} =\)


(A) –16/25

(B) 16/25

(C) 25/16

(D) 16

(E) 25

\(\displaystyle\frac{0.08^{-4}}{0.04^{-3}}
=\frac{1}{0.08^4} : \frac{1}{0.04^3}
=\frac{0.04^3}{0.08^4} \\
=\frac{(\frac{4}{100})^3}{(\frac{8}{100})^4}
=\frac{(\frac{2^2}{10^2})^3}{(\frac{2^3}{10^2})^4}
=\frac{\frac{2^6}{10^6}}{\frac{2^{12}}{10^8}} \\
=\frac{2^6}{10^6} \times \frac{10^8}{2^{12}}
=\frac{10^2}{2^6} \\
=\frac{2^2\times 5^2}{2^6}
=\frac{5^2}{2^4}
=\frac{25}{16}\)

The answer is C
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Bunuel
\(\frac{(0.08)^{(–4)}}{(0.04)^{(–3)}} =\)


(A) –16/25

(B) 16/25

(C) 25/16

(D) 16

(E) 25

\(\frac{(0.08)^{(–4)}}{(0.04)^{(–3)}}\)
= \(\frac{(0.04)^{(3)}}{(0.08)^{(4)}}\)
= \((0.04/0.08)^{(3)}*(1/0.08)\)
= \((1/2)^{(3)}*(100/8)\)
= \((1/8)*(25/2)\)
= \(\frac{25}{16}\)

Correct Answer C.
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Bunuel
\(\frac{(0.08)^{(–4)}}{(0.04)^{(–3)}} =\)


(A) –16/25

(B) 16/25

(C) 25/16

(D) 16

(E) 25

Notice that 0.08/0.04 = 2; thus:

(0.08)^(-4)/(0.04)^(-3)

[(0.08)^(-3) x (0.08)^(-1)]/(0.04)^(-3)

2^(-3) x (0.08)^-1

1/2^3 x 1/(8/100)

1/8 x 100/8

1/8 x 25/2

25/16

Answer: C
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