ronny123
chetan2u
techiesam
Two person start walking on a road that diverge at angle of 120 degree.If they walk at the rate of 2kmph and 3 3kmph relatively, then find the distance between them after 4 hours or find the value of c as given in the image attached below.
A.5
B. 4√19
C.7
D. 8√19
E. √19
hi,
Trignometry is NOT tested in GMAT so there has to be another solution..
SEE att image..
Draw an altitude from A to BC extende at D..
Triangle ACD is a right angle triangle, whose HYP is 2*4..
rest sides are CD-4, opp 30 degree and AD - \(4\sqrt{3}\), opp 60 degree..Now take ADB..
c is hyp..
BD = 3*4 + 4 = 16 and AD = \(4\sqrt{3}\)..
HYp = AC = \(\sqrt{16^2+(4*Sq Root 3})^2\) = \(\sqrt{304}\) = \(4\sqrt{19}\)
B
hi,
Don't be offended but isn't the maths inherent to subject correct ?
if you use c^2 = a^2 + b^2 - 2abcos(120)
= a^2 + b^2 - 2ab(-1/2)
= a^2 + b^2 + ab
a = 2 x 4 = 8
b = 3 x 4 = 12
Putting these values,
c^2 = 8^2 + 12^2 + (8)(12)
= 64 +144 + 96
= 304
c = 4√‾19
Saying Trigo isn't tested on the GMAT isn't changing the solution, my friend
Again, no offense meant.
Hi,
It is not meant for you ..
It is for people who are preparing for GMAT so that they do not get into the area where it is NOT required..
You are most welcome to learn anything being tested or not,
BUT people who are interested in just GMAT should not go away with thought that they have to do trignometry to do this Q..
I don't require to take offence or offend you, I am giving the WAY one should think about this solution