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Sub 505 (Easy)|   Remainders|                        
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AbdurRakib
The quotient when a certain number is divided by \(\frac{2}{3}\) is \(\frac{9}{2}\). What is the number?

A. \(\frac{4}{27}\)

B. \(\frac{1}{3}\)

C. 3

D. 6

E. \(\frac{27}{4}\)

\(\frac{2}{3}*\frac{9}{2} = 3\)

Hence, answer will be (C) 3
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AbdurRakib
The quotient when a certain number is divided by \(\frac{2}{3}\) is \(\frac{9}{2}\). What is the number?

A. \(\frac{4}{27}\)

B. \(\frac{1}{3}\)

C. 3

D. 6

E. \(\frac{27}{4}\)

n *\(\frac{3}{2}\) = \(\frac{9}{2}\)
=> n = 3

C is the answer.

Alternatively
N = PQ + R
N = \(\frac{2}{3}\)*\(\frac{9}{2}\) + R
N = 3 + R
The Question doesn't mention if the division has a remainder, so R = 0
=> N = 3
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The quotient when a certain number is divided by \(\frac{2}{3}\) is \(\frac{9}{2}\). What is the number?

A. \(\frac{4}{27}\)

B. \(\frac{1}{3}\)

C. 3

D. 6

E. \(\frac{27}{4}\)
If \(\frac{N}{\frac{2}{3}}\) =\(\frac{9}{2}\)

Then \(\frac{2}{3} * \frac{9}{2}\) = N =\(\frac{18}{6} = 3\)

Answer C
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AbdurRakib
The quotient when a certain number is divided by \(\frac{2}{3}\) is \(\frac{9}{2}\). What is the number?

A. \(\frac{4}{27}\)

B. \(\frac{1}{3}\)

C. 3

D. 6

E. \(\frac{27}{4}\)

n/(2/3) = 9/2

3n/2 = 9/2

6n = 18

n = 3

Answer: C
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AbdurRakib
The quotient when a certain number is divided by \(\frac{2}{3}\) is \(\frac{9}{2}\). What is the number?

A. \(\frac{4}{27}\)

B. \(\frac{1}{3}\)

C. 3

D. 6

E. \(\frac{27}{4}\)
Let,
the number is x

x/2/3=9/2
=>x=9/2*2/3=3

Answer is C

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AbdurRakib
The quotient when a certain number is divided by \(\frac{2}{3}\) is \(\frac{9}{2}\). What is the number?

A. \(\frac{4}{27}\)

B. \(\frac{1}{3}\)

C. 3

D. 6

E. \(\frac{27}{4}\)

X divided by 2/3 is a 9 / 2, so X times 3 / 2 is

going to be equal to 9 / 2; the 2 gets cancelled out, the 3 gets reduced.

X equals 3. That's it; correct answer choice is C.
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AbdurRakib
The quotient when a certain number is divided by \(\frac{2}{3}\) is \(\frac{9}{2}\). What is the number?

A. \(\frac{4}{27}\)

B. \(\frac{1}{3}\)

C. 3

D. 6

E. \(\frac{27}{4}\)

Answer: Option C

Video solution by GMATinsight

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Correct Option : C : 3
Formula : Dividend = (Quotient * Divisor) + Remainder
Dividend = x
Quotient = 9/2
Divisor = 2/3
Reminder = 0
x = 9/2 * 2/3 + 0
x = 3
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pushpitkc
Consider the number for which the quotient is \(\frac{9}{2}\) as x

Since x divided by \(\frac{2}{3}\) gives us the quotient \(\frac{9}{2}\)
x * \(\frac{3}{2}\) = \(\frac{9}{2}\)

x = \(\frac{9}{2}\)*\(\frac{2}{3}\) = 3(Option C)

How can we assume that remainder is zero here?
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Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
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avigutman
Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1

When I was attempting to solve this problem, I took the following steps:
x/(2/3)=9/2
-->x=(9/2)*(3/2)

In other words, I multiplied by the reciprocal. To clarify, you only multiply by the reciprocal of the fraction for terms on the same side of the equal sign?

Thank you!
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woohoo921
When I was attempting to solve this problem, I took the following steps:
x/(2/3)=9/2
-->x=(9/2)*(3/2)

In other words, I multiplied by the reciprocal. To clarify, you only multiply by the reciprocal of the fraction for terms on the same side of the equal sign?
woohoo921 I almost missed this - please always tag me if you want my take.
Dividing by 5 is the same thing as multiplying by 1/5, right?
And, dividing by 1/5 is the same as multiplying by 5.
By the same token, dividing by 2/3 is the same as multiplying by 3/2.
This is always true, whether you're looking at an individual expression or at one side of an equation.
It seems that you chose to simplify the equation by expanding it (multiplying both sides by the same factor). For example (replacing 2/3 with 'a'), if the equation was:
x/a=9/2
You'd multiply both sides by a and get x = (9/2)a. That's a perfectly reasonable thing to do. In our case, it would look like this:
x/(2/3)=9/2
-->x=(9/2)*(2/3)
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avigutman - my concern is regarding the wording used in this official question - Can we use the word ‘quotient’ to refer to a fraction which cannot be expressed as an integer? Thanks.

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Braintree
avigutman - my concern is regarding the wording used in this official question - Can we use the word ‘quotient’ to refer to a fraction which cannot be expressed as an integer?
Yes. Braintree. Definition of "quotient" from https://www.merriam-webster.com:
the number resulting from the division of one number by another.
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