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C1=Va/(Va+Vw) where, C -concentration; Va - volume of alcohol, Vm - volume of water. Vtotal=(Va+Vw) - total volume.

C1=Va/(Va+Vw)

C2=(Va+dVa)/(Va+Vw+dVa+dVw) where dVa - additional volume of alcohol, dVm - additional volume of water

C2=(C1*Vtotal+dVa)/(Vtotal+dVa+dVw)

C2=(0.05*50+1.5)/(50+1.5+8.5)=4/60=1/15~0.06666666 ==>6,(6)%
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bmwhype2
A 50 liter solution of alcohol and water is 5% alcohol. If 1.5 liters of alcohol and 8.5 liters are added to the solution, what percent of the solution produced is alcohol?

= 4/60
= 1/15
= 6.67%


5% of 50 = 2.5 liters of alcohol

10 liters added
50+10=60

2.5+1.5=4

4/60=2/30=1/15=6.67%
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Dakinemon
I disagree

50L * .05 = 2.5 L of alc, 50L - 2.5L = 47.5L of water

2.5 + 1.5 = 4L of alcohol in new solution

47.5L + 8.5L = 56L of water

4L / 56L = 1/14

this is ~7%


u took the percentage of alcohol from total water
Q asked for percentage of alcohol from total solution
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5% alcohol in 50 litre solution = 2.5 litres
adding 1.5 litres to it makes it total of 4 litres
total solution = 60 litres
% alcohol = 4/60 * 100 = 6.666667%
Answer - D
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let x=% of alcohol in final solution
2.5+1.5=60x
x=1/15=6 2/3%
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I am not clear on this question, shouldn't the answer be 7%?

As new solution will be 4 Ltrs Alcohol & 56 Ltrs of Water = 60 in Total

\(4/60*100 = 6.66\)

Please advise if you I am going wrong here?

Bunuel, Abhishek009 - Please advise
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ydmuley

A 50-liter solution of alcohol and water is 5 percent alcohol. If 1.5 liters of alcohol and 8.5 liters of water are added to this solution,
what percent of the solution produced is alcohol?

we are asked to find the exact percent- why are you rounding off the value?

\(\frac{4}{60}\) * 100 = \(\frac{20}{3}\) = 6 \(\frac{2}{3}\) = Ans is D
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bmwhype2
A 50-liter solution of alcohol and water is 5 percent alcohol. If 1.5 liters of alcohol and 8.5 liters of water are added to this solution, what percent of the solution produced is alcohol?

A. 5.5%
B. 6%
C. 6 1/3%
D. 6 2/3%
E. 7%

Solution \(= 50\) liters

Alcohol is 5% of 50 \(= \frac{5}{100} * 50 = 2.5\) liters

1.5 liters of alcohol added. Therefore Total liters of alcohol \(= 2.5 + 1.5 = 4\) liters.

1.5 liters of alcohol and 8.5 liters of water is added to solution \(= 50 + 1.5 + 8.5 = 60\) liters.

Percentage of alcohol in new solution \(= \frac{4}{60} * 100 = 66.67\)% or \(6 \frac{2}{3}\) % . Answer (D) ...
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bmwhype2
A 50-liter solution of alcohol and water is 5 percent alcohol. If 1.5 liters of alcohol and 8.5 liters of water are added to this solution, what percent of the solution produced is alcohol?

A. 5.5%
B. 6%
C. 6 1/3%
D. 6 2/3%
E. 7%

Solution \(= 50\) liters

Alcohol is 5% of 50 \(= \frac{5}{100} * 50 = 2.5\) liters

1.5 liters of alcohol added. Therefore Total liters of alcohol \(= 2.5 + 1.5 = 4\) liters.

1.5 liters of alcohol and 8.5 liters added to solution \(= 50 + 1.5 + 8.5 = 60\) liters.

Percentage of alcohol in new solution \(= \frac{4}{60} * 100 = 66.67\)% or \(6 \frac{2}{3}\) % . Answer (D) ...

Once again thanks for the explanation, it was helpful. Where I went wrong is incorrectly reading option C & D as \(62/3\) and \(61/3\)

Hence, I was left with option E which was more closer to the number.

Good one :-D
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Leo8
ydmuley

A 50-liter solution of alcohol and water is 5 percent alcohol. If 1.5 liters of alcohol and 8.5 liters of water are added to this solution,
what percent of the solution produced is alcohol?

we are asked to find the exact percent- why are you rounding off the value?

\(\frac{4}{60}\) * 100 = \(\frac{20}{3}\) = 6 \(\frac{2}{3}\) = Ans is D


Got it Leo8 - Thank you. I misread the answer choices as 61/3 & 62/3
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bmwhype2
A 50-liter solution of alcohol and water is 5 percent alcohol. If 1.5 liters of alcohol and 8.5 liters of water are added to this solution, what percent of the solution produced is alcohol?

A. 5.5%
B. 6%
C. 6 1/3%
D. 6 2/3%
E. 7%

presently out of 50 ltrs alcohol is 2.5 ltrs and 47.5 ltrs water
later 1.5 ltrs alcohol added ana 8.5 ltrs water added
4 ltrs alcohol and 56 ltrs water
4/60 ; 1/15 ; ~6.66%
option D
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= 4/60
= 1/15
= 6.67%

Answer is D.
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Can anyone solve this by alligation method?
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I used a table to solve this.

..............Original......+Alcohol.....+Water.....Final

Alcohol....2.5 lit...........1.5l.............0l.........4l

Water......47.5 lit.........0l................8.5l.......56l

Total.......50 lit............1.5l.............8.5l........60l

Now, we just divide 4 by 60, to get 6.67%.

Thus, answer is D.
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Anki111
Can anyone solve this by alligation method?

We have a 50 ltr solution or 5% alcohol.
If we add 1.5 ltr alcohol and 8.5 ltr water, it means we are adding a 10 ltr solution of 15% alcohol (because concentration of alcohol is 1.5/10 = 15%)

Use the scale method:

5% -------------------------- 15%
(50).................................(10)

The 10% distance between 5% and 15% is divided in the ratio 1:5 so \(Cavg = 5 + (\frac{1}{6})*10 = 6(\frac{2}{3})\)%

Answer (D)

Check out these videos on how to use the scale method and how to apply it to mixtures:
https://www.youtube.com/watch?v=_GOAU7moZ2Q
https://www.youtube.com/watch?v=VdBl9Hw0HBg

and these posts:
https://anaprep.com/arithmetic-weighted-averages/
https://anaprep.com/arithmetic-mixtures/
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