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02 Jun 2017, 01:19
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We define the average (harmonic mean) as the reciprocal of the average (arithmetic mean) of reciprocals. What is the average (harmonic mean) of 2, 3, and 6?
A. 1/3
B. 1/2
C. 1
D. 2
E. 3
A. 1/3
B. 1/2
C. 1
D. 2
E. 3
02 Jun 2017, 02:00
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Harmonic mean = 1/A
A ==> Average of the reciprocals of 2, 3 and 6 = (1/2 + 1/3 + 1/6)/3 = 1/3
Hence H = 3 Answer option E.
A ==> Average of the reciprocals of 2, 3 and 6 = (1/2 + 1/3 + 1/6)/3 = 1/3
Hence H = 3 Answer option E.
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02 Jun 2017, 23:16
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MathRevolution
We define the average (harmonic mean) as the reciprocal of the average (arithmetic mean) of reciprocals. What is the average (harmonic mean) of 2, 3, and 6?
A. 1/3
B. 1/2
C. 1
D. 2
E. 3
A. 1/3
B. 1/2
C. 1
D. 2
E. 3
Average (Arithmetic mean) of reciprocals of 2,3 and 6 = \((\frac{1}{2} + \frac{1}{3} + \frac{1}{6}) /3\) = \((\frac{3+2+1}{6})/3\) = \((\frac{6}{6})/3\) = \(\frac{1}{3}\)
Harmonic mean is the reciprocal of the average (arithmetic mean) of reciprocals = \(\frac{3}{1}\) = 3
Answer E...
