nithinjohn wrote:
GMATinsight wrote:
Bunuel wrote:
What is the area of the 6 rectangles shown in the figure?
(1) The area of rectangle D is twice the area of rectangle E.
(2) The area of rectangle A is equal to the area of rectangle F and the area of rectangle E, which is 20, is equal to the area of rectangle F.
Attachment:
The attachment image004.jpg is no longer available
After combining the two statement we get
Area of E = Area of F = Area of A = 20
Now statement 1 gives, Area of D = 40
i.e. Area of B = Area of C = (1/2) Area of E or F = 10
Now we have area of each rectangle hence
SUFFICIENT
Answer:option C
Could you please explain how you got the area of B and C as 10? I did not understand the part where you deduced that the AREA of B=1/2( Area of E or F)
Hi
nithinjohn,
Please refer the enclosed diagram, you would notice that
Area of rectangle B=area of rectangle C=z*k
We have x*y=40---(1), x*z=20----(2), and y*k=20 or, k=\(\frac{20}{y}\)---(3)
From (1)&(2),we have z=\(\frac{y}{2}\)
So z*k=(y/2)*(20/y)=10, which is 1/2 times area of E or F
Hope it helps.
Attachments
6 Rectangle area.jpg [ 19.36 KiB | Viewed 153 times ]
_________________
Regards,
PKN
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40% (01:53) correct 
