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Difficulty:
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Question Stats:
80% (01:15) correct
20%
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wrong
based on 269
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What is the largest possible value of \(c\) if \(5c + (d-12)^2 = 235\) ?
A) 17
B) 25
C) 35
D) 42
E) 47
A) 17
B) 25
C) 35
D) 42
E) 47
24 Jul 2015, 05:15
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noTh1ng
What is the largest possible value of \(c\) if \(5c + (d-12)^2 = 235\) ?
A) 17
B) 25
C) 35
D) 42
E) 47
I was not able to solve this algebraically...
A) 17
B) 25
C) 35
D) 42
E) 47
I was not able to solve this algebraically...
To maximize c, we should minimize (d-12)^2. (d-12)^2 is a square of a number, thus its smallest possible value is 0 (for d = 12).
In this case we'd have 5c + 0 = 235 --> c = 47.
Answer: E.
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24 Jul 2015, 05:21
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noTh1ng
What is the largest possible value of \(c\) if \(5c + (d-12)^2 = 235\) ?
A) 17
B) 25
C) 35
D) 42
E) 47
I was not able to solve this algebraically...
A) 17
B) 25
C) 35
D) 42
E) 47
I was not able to solve this algebraically...
You need to remember that the minimum value of a square term is 0. Any square \(\geq\) 0
Thus, the given equation is : \(5c + (d-12)^2 = 235\) ---> \(5c = 235 - (d-12)^2\)
Now, based on the above manipulation, we can see that 235- a positive quantity = will only decrease the value of c.
Thus the maximum value of c will be obtained when (d-12)^2 = 0 ---> d =12
Thus the maximum value of c = (235-0 )/5 = 47. E is the correct answer.
