Last visit was: 15 Dec 2024, 00:52 It is currently 15 Dec 2024, 00:52
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 14 Dec 2024
Posts: 97,877
Own Kudos:
685,946
 []
Given Kudos: 88,271
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 97,877
Kudos: 685,946
 []
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
User avatar
MsInvBanker
Joined: 23 May 2018
Last visit: 16 Jun 2021
Posts: 658
Own Kudos:
Given Kudos: 45
Location: Pakistan
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
PKN
Joined: 01 Oct 2017
Last visit: 20 Apr 2023
Posts: 821
Own Kudos:
1,435
 []
Given Kudos: 41
Status:Learning stage
WE:Supply Chain Management (Energy)
Posts: 821
Kudos: 1,435
 []
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
MsInvBanker
Joined: 23 May 2018
Last visit: 16 Jun 2021
Posts: 658
Own Kudos:
Given Kudos: 45
Location: Pakistan
Kudos
Add Kudos
Bookmarks
Bookmark this Post
PKN
HinaTabassum
Looking at the diagram I can say that the angle ACB is 45° and I did not have to read any statement to get to this figure. Where am I wrong here Bunuel

I do not understand how do the values in the statements help.

Hi HinaTabassum,

We mustn't infer or conclude anything just looking at the diagram in GMAT(If specifically it's not mentioned).

Solution:-

In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.

Here, AB is the intercepted arc, Angle AOB & Angle ACB are the measure of central angle and inscribed angle under arc AB respectively.

Refer the enclosed diagram, question stem : What is the measure of x ?

from st1, radius=5 & from st2, arc AB=10

So we can write Arc \(AB=2\pi*r(\frac{2x}{2\pi})\)
Or, \(10=2\pi*5(\frac{2*x}{2\pi})\)

We can solve the above equation and determine the value of 'x'.

Sufficient.

Ans. (C)

You may raise further queries(if any)

PKN I remember reading in many places that every diagram on the GMAT is drawn to scale.

I see how you solved it. I believe I relied on the pictionary here more than the numbers.
User avatar
PKN
Joined: 01 Oct 2017
Last visit: 20 Apr 2023
Posts: 821
Own Kudos:
1,435
 []
Given Kudos: 41
Status:Learning stage
WE:Supply Chain Management (Energy)
Posts: 821
Kudos: 1,435
 []
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
HinaTabassum
PKN
HinaTabassum
Looking at the diagram I can say that the angle ACB is 45° and I did not have to read any statement to get to this figure. Where am I wrong here Bunuel

I do not understand how do the values in the statements help.

Hi HinaTabassum,

We mustn't infer or conclude anything just looking at the diagram in GMAT(If specifically it's not mentioned).

Solution:-

In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.

Here, AB is the intercepted arc, Angle AOB & Angle ACB are the measure of central angle and inscribed angle under arc AB respectively.

Refer the enclosed diagram, question stem : What is the measure of x ?

from st1, radius=5 & from st2, arc AB=10

So we can write Arc \(AB=2\pi*r(\frac{2x}{2\pi})\)
Or, \(10=2\pi*5(\frac{2*x}{2\pi})\)

We can solve the above equation and determine the value of 'x'.

Sufficient.

Ans. (C)

You may raise further queries(if any)

PKN I remember reading in many places that every diagram on the GMAT is drawn to scale.

I see how you solved it. I believe I relied on the pictionary here more than the numbers.

Hi HinaTabassum,

You may refer the below lines what test makers say:-

OFFICIAL GUIDE:

Problem Solving
Figures: All figures accompanying problem solving questions are intended to provide information useful in solving the problems. Figures are drawn as accurately as possible. Exceptions will be clearly noted. Lines shown as straight are straight, and lines that appear jagged are also straight. The positions of points, angles, regions, etc., exist in the order shown, and angle measures are greater than zero. All figures lie in a plane unless otherwise indicated.

Data Sufficiency:
Figures:
• Figures conform to the information given in the question, but will not necessarily conform to the additional information given in statements (1) and (2).
• Lines shown as straight are straight, and lines that appear jagged are also straight.
• The positions of points, angles, regions, etc., exist in the order shown, and angle measures are greater than zero.

• All figures lie in a plane unless otherwise indicated.
https://gmatclub.com/forum/gmat-trick-r ... 01412.html

Hope this helps.
User avatar
saurabh9gupta
Joined: 10 Jan 2013
Last visit: 28 Jul 2023
Posts: 265
Own Kudos:
Given Kudos: 201
Location: India
Concentration: General Management, Strategy
GRE 1: Q163 V155
GPA: 3.95
Products:
GRE 1: Q163 V155
Posts: 265
Kudos: 171
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Here none of the statements are sufficient.

We will have to combine both the statements

Now if we join OB then
OA = OB = OC = 5

one can calculate angle AOB

(THETA/360)* 2*PI*R = 10.

angles can be calculated so C

Posted from my mobile device
User avatar
MsInvBanker
Joined: 23 May 2018
Last visit: 16 Jun 2021
Posts: 658
Own Kudos:
Given Kudos: 45
Location: Pakistan
Kudos
Add Kudos
Bookmarks
Bookmark this Post
PKN
HinaTabassum
PKN

Hi HinaTabassum,

We mustn't infer or conclude anything just looking at the diagram in GMAT(If specifically it's not mentioned).

Solution:-

In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.

Here, AB is the intercepted arc, Angle AOB & Angle ACB are the measure of central angle and inscribed angle under arc AB respectively.

Refer the enclosed diagram, question stem : What is the measure of x ?

from st1, radius=5 & from st2, arc AB=10

So we can write Arc \(AB=2\pi*r(\frac{2x}{2\pi})\)
Or, \(10=2\pi*5(\frac{2*x}{2\pi})\)

We can solve the above equation and determine the value of 'x'.

Sufficient.

Ans. (C)

You may raise further queries(if any)

PKN I remember reading in many places that every diagram on the GMAT is drawn to scale.

I see how you solved it. I believe I relied on the pictionary here more than the numbers.

Hi HinaTabassum,

You may refer the below lines what test makers say:-

OFFICIAL GUIDE:

Problem Solving
Figures: All figures accompanying problem solving questions are intended to provide information useful in solving the problems. Figures are drawn as accurately as possible. Exceptions will be clearly noted. Lines shown as straight are straight, and lines that appear jagged are also straight. The positions of points, angles, regions, etc., exist in the order shown, and angle measures are greater than zero. All figures lie in a plane unless otherwise indicated.

Data Sufficiency:
Figures:
• Figures conform to the information given in the question, but will not necessarily conform to the additional information given in statements (1) and (2).
• Lines shown as straight are straight, and lines that appear jagged are also straight.
• The positions of points, angles, regions, etc., exist in the order shown, and angle measures are greater than zero.

• All figures lie in a plane unless otherwise indicated.
https://gmatclub.com/forum/gmat-trick-r ... 01412.html

Hope this helps.


Thank you PKN for the help. :)
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 35,822
Own Kudos:
Posts: 35,822
Kudos: 930
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderator:
Math Expert
97877 posts