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# What is the value of (39^2/2^4)/(13^3/4^2)

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Math Expert
Joined: 02 Sep 2009
Posts: 57146
What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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15 Jul 2019, 23:49
00:00

Difficulty:

5% (low)

Question Stats:

98% (00:50) correct 2% (01:38) wrong based on 41 sessions

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What is the value of $$\frac{\frac{39^2}{2^4}}{\frac{13^3}{4^2}}$$ ?

A. $$\frac{13}{2}$$

B. $$\frac{9}{2}$$

C. $$\frac{3}{2}$$

D. $$\frac{3}{13}$$

E. $$\frac{9}{13}$$

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Joined: 26 Jan 2016
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Re: What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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16 Jul 2019, 00:06
(39^2/2^4)/(13^3/4^2)
= ((13*3)^2/2^4)/(13^3/2^(2*2))
= ((3)^2)/(13^1)=9/13

Hence E

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Re: What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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16 Jul 2019, 00:12
Bunuel wrote:
What is the value of $$\frac{\frac{39^2}{2^4}}{\frac{13^3}{4^2}}$$ ?

A. $$\frac{13}{2}$$

B. $$\frac{9}{2}$$

C. $$\frac{3}{2}$$

D. $$\frac{3}{13}$$

E. $$\frac{9}{13}$$

$$\frac{\frac{39^2}{2^4}}{\frac{13^3}{4^2}}$$
$$=\frac{\frac{3^2*13^2}{2^4}}{\frac{13^3}{2^4}}$$
$$=\frac{3^2*13^2}{13^3}$$
$$=\frac{3^2}{13}$$
$$=\frac{9}{13}$$

IMO E
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Re: What is the value of (39^2/2^4)/(13^3/4^2)  [#permalink]

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16 Jul 2019, 00:38
Answer is E = 39^2 *4^2/ 2^4 * 13^3 = 13^ 2^2/ 13^3 = 9/13
Re: What is the value of (39^2/2^4)/(13^3/4^2)   [#permalink] 16 Jul 2019, 00:38
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