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Solve the equation
\(\frac{4}{b} = \frac{a^2+5b}{5a}\)
or
\(\frac{1}{b} = \frac{a^2+5b}{20a}\)
divide entire side by 1
\(b = \frac{20a}{a^2 +5b}\)
thus A
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Which of the following is b equal to in terms of a if a> 0 and 4/b = a/5 + 5/a?


a) 20a/(a^2 + 25) --> correct: 4/b = a/5 + 5/a = (a^2+25)/5a => b = 20a/(a^2+25)
b) 5a/(a^2 + 25)
c) 20/(a^2 +25)
d) (a^2 +25)/(20a)
e) (20a +5)/(a^2 + 25a
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