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17 Mar 2019, 11:48
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X, Y and Z are three positive integers such that the least common multiple of X & Y is 12, while the least common multiple of Y & Z is 18. Which of the following could be the value of Y?
I) 6
II) 9
III) 3
IV) 4
A. III only
B. IV only
C. I and III only
D. III and IV only
E. I and III and IV only
I) 6
II) 9
III) 3
IV) 4
A. III only
B. IV only
C. I and III only
D. III and IV only
E. I and III and IV only
17 Mar 2019, 23:22
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amanvermagmat
X, Y and Z are three positive integers such that the least common multiple of X & Y is 12, while the least common multiple of Y & Z is 18. Which of the following could be the value of Y?
I) 6
II) 9
III) 3
IV) 4
A. III only
B. IV only
C. I and III only
D. III and IV only
E. I and III and IV only
I) 6
II) 9
III) 3
IV) 4
A. III only
B. IV only
C. I and III only
D. III and IV only
E. I and III and IV only
X*Y =12 ; 2^2 * 3 or 6*2
Y*Z= 18 ; 3^2*2 or 6*3
so value of y = 6 or 3
IMO C
22 May 2019, 18:55
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amanvermagmat
X, Y and Z are three positive integers such that the least common multiple of X & Y is 12, while the least common multiple of Y & Z is 18. Which of the following could be the value of Y?
I) 6
II) 9
III) 3
IV) 4
A. III only
B. IV only
C. I and III only
D. III and IV only
E. I and III and IV only
I) 6
II) 9
III) 3
IV) 4
A. III only
B. IV only
C. I and III only
D. III and IV only
E. I and III and IV only
12: 2,2,3
18: 2,3,3
1. Maximum number of '2' that can be is only 1, coz 18 has only 1 '2'
2. Simultaneously, max number of '3' that can be also only 1, coz 12 has only 1 '3'
So, possible varients of Y: 2,3 or 2*3
So the answer is C
