Bunuel
A, B and C can complete a piece of work in 24 days, 40 days and 60 days, respectively. In how many days was the piece of work completed?
(1) A, B and C started working together, and A continued to work till the end.
(2) A, B and C started working together, B and C left the work 2 days and 7 days, respectively, before the completion of the work.
A does 1/24 of work in 1 day
B does 1/40 of work in 1 day
C does 1/60 of work in 1 day
(1) gives us A+B+C started together and A continued till the end but we do not know for how many days B & C worked
Not sufficient
(2) A+B+C started together, B worked for 2 days and C worked for 7 Days
We can say that
For 2 days (A+B+C)
For 5 days (A+C)
For the rest of days A alone
Lets assume the work to be 240 units
A works for 10 units/day
B works for 6 units/day
C works for 4 units/day
A+B+C = 20 units/day
A+C = 14 units/day
But we don't know if A continued till the end (Cannot assume that A completed the work after 7 days) hence Not sufficient
On combining both we can form the equation
2*20 + 5*14 + x*10 = 240
We can find x and add 7 days to it to get the answer
Hence C