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A flat patio was built alongside a house as shown in the figure above.
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14 Oct 2015, 20:35
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Re: A flat patio was built alongside a house as shown in the figure above.
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14 Oct 2015, 21:21
Bunuel wrote: A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet? (A) 800 (B) 875 (C) 1,000 (D) 1,100 (E) 1,125 Kudos for a correct solution.Attachment: The attachment 20151015_0834.png is no longer available CHeck teh explanation in figure where the area of Patio has been divided into two rectangles one of Dimension 35X20 Other of Dimension 15X20 Answer: option C
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Re: A flat patio was built alongside a house as shown in the figure above.
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14 Oct 2015, 20:59
Area of Patio = area of uncovered part of rectangle = 40x35  20x20= 1000 square feet Answer C
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Re: A flat patio was built alongside a house as shown in the figure above.
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14 Oct 2015, 23:51
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer. A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet? (A) 800 (B) 875 (C) 1,000 (D) 1,100 (E) 1,125 Let the width of the overlapped rectangle be x feet and the length be y feet. Then x= 4020= 20 feet, y= 3515 = 20 feet. So the area of the overlapped rectangle is 400= 20 * 20 square feet. The area of patio is, therefore, 40*35 – 400 = 1400400 = 1000 square feet. The answer is (C).
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Re: A flat patio was built alongside a house as shown in the figure above.
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17 Nov 2016, 08:20
Bunuel wrote: A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet? (A) 800 (B) 875 (C) 1,000 (D) 1,100 (E) 1,125 Kudos for a correct solution.Attachment: 20151015_0834.png Total area of patio, 40*35=1400 Overlap part:4020=20 3515=20 So, 20*20=400 So, the area of patio after removing house part=1400400=1100. So, the correct answer is D
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Re: A flat patio was built alongside a house as shown in the figure above.
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12 Jan 2017, 05:21
Area of Patio = area of uncovered part of rectangle = 40x35  20x20= 1000



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Re: A flat patio was built alongside a house as shown in the figure above.
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18 Jan 2017, 16:52
GMATinsight wrote: Bunuel wrote: A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet? (A) 800 (B) 875 (C) 1,000 (D) 1,100 (E) 1,125 Kudos for a correct solution.Attachment: 20151015_0834.png CHeck teh explanation in figure where the area of Patio has been divided into two rectangles one of Dimension 35X20 Other of Dimension 15X20 Answer: option C As mentioned Patio is a square , Area of a square is S^2 All sides should be same as Square Then how can we multiply Individual Areas 20x15 and 20x35?? Pls explain. Thanks
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Re: A flat patio was built alongside a house as shown in the figure above.
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23 Jan 2017, 07:52
Area of Patio = area of uncovered part of rectangle = 40x35  20x20 = 1000



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Re: A flat patio was built alongside a house as shown in the figure above.
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27 Jan 2017, 22:12
kanusha wrote: GMATinsight wrote: Bunuel wrote: A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet? (A) 800 (B) 875 (C) 1,000 (D) 1,100 (E) 1,125 Kudos for a correct solution.Attachment: 20151015_0834.png CHeck teh explanation in figure where the area of Patio has been divided into two rectangles one of Dimension 35X20 Other of Dimension 15X20 Answer: option C As mentioned Patio is a square , Area of a square is S^2 All sides should be same as Square Then how can we multiply Individual Areas 20x15 and 20x35?? Pls explain. Thanks Hey, It is nowhere mentioned in the question that the Patio is a square. I guess you must have got confused with the following line  "what is the area of the patio in square feet?"This simply means that we need to find the area of the patio and the unit of the area is \((feet)^2\) and that will happen only when we express each of the sides of the patio in term of feet and not some other measurement like meters, centimeters etc. Thanks, Saquib Quant Expert eGMATRegister for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the realtime guidance of our Experts
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Re: A flat patio was built alongside a house as shown in the figure above.
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07 Mar 2017, 03:44
patio has dimension 40*35 therefore area=1400 why the overlapped area has to subtracted from it? even though the question asks what is area of patio



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Re: A flat patio was built alongside a house as shown in the figure above.
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09 Apr 2018, 10:33
Bunuel wrote: A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet? (A) 800 (B) 875 (C) 1,000 (D) 1,100 (E) 1,125 Kudos for a correct solution.Attachment: 20151015_0834.png Area of the patio (including the part overlapped by the house) = L*W = 35*40 = 1400 Now, the area (square) of the overlapped part = side*side = 20*20 = 400 Area of the patio = 1400400 = 1000 Answer is option C.
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Re: A flat patio was built alongside a house as shown in the figure above.
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