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# A flat patio was built alongside a house as shown in the figure above.

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Math Expert
Joined: 02 Sep 2009
Posts: 47038
A flat patio was built alongside a house as shown in the figure above. [#permalink]

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14 Oct 2015, 21:35
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5% (low)

Question Stats:

89% (01:01) correct 11% (01:10) wrong based on 896 sessions

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A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet?

(A) 800
(B) 875
(C) 1,000
(D) 1,100
(E) 1,125

Kudos for a correct solution.

Attachment:

2015-10-15_0834.png [ 6.66 KiB | Viewed 9255 times ]

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Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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14 Oct 2015, 22:21
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Bunuel wrote:

A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet?

(A) 800
(B) 875
(C) 1,000
(D) 1,100
(E) 1,125

Kudos for a correct solution.

Attachment:
The attachment 2015-10-15_0834.png is no longer available

CHeck teh explanation in figure where the area of Patio has been divided into two rectangles
one of Dimension 35X20
Other of Dimension 15X20

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##### General Discussion
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Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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14 Oct 2015, 21:59
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1
Area of Patio = area of uncovered part of rectangle
= 40x35 - 20x20= 1000 square feet
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Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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15 Oct 2015, 00:51
1
Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.

A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet?
(A) 800
(B) 875
(C) 1,000
(D) 1,100
(E) 1,125

Let the width of the overlapped rectangle be x feet and the length be y feet.
Then x= 40-20= 20 feet, y= 35-15 = 20 feet.
So the area of the overlapped rectangle is 400= 20 * 20 square feet.
The area of patio is, therefore, 40*35 – 400 = 1400-400 = 1000 square feet.
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Posts: 430
Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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17 Nov 2016, 09:20
1
1
Bunuel wrote:

A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet?

(A) 800
(B) 875
(C) 1,000
(D) 1,100
(E) 1,125

Kudos for a correct solution.

Attachment:
2015-10-15_0834.png

Total area of patio, 40*35=1400
Overlap part:
40-20=20
35-15=20
So, 20*20=400
So, the area of patio after removing house part=1400-400=1100.
So, the correct answer is D
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Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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12 Jan 2017, 06:21
Area of Patio = area of uncovered part of rectangle
= 40x35 - 20x20= 1000
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Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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18 Jan 2017, 17:52
GMATinsight wrote:
Bunuel wrote:

A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet?

(A) 800
(B) 875
(C) 1,000
(D) 1,100
(E) 1,125

Kudos for a correct solution.

Attachment:
2015-10-15_0834.png

CHeck teh explanation in figure where the area of Patio has been divided into two rectangles
one of Dimension 35X20
Other of Dimension 15X20

As mentioned Patio is a square , Area of a square is S^2
All sides should be same as Square
Then how can we multiply Individual Areas 20x15 and 20x35??
Pls explain. Thanks
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Senior Manager
Joined: 02 Jan 2017
Posts: 314
Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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23 Jan 2017, 08:52
Area of Patio = area of uncovered part of rectangle
= 40x35 - 20x20 = 1000
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Joined: 04 Jan 2015
Posts: 1755
Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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27 Jan 2017, 23:12
kanusha wrote:
GMATinsight wrote:
Bunuel wrote:

A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet?

(A) 800
(B) 875
(C) 1,000
(D) 1,100
(E) 1,125

Kudos for a correct solution.

Attachment:
2015-10-15_0834.png

CHeck teh explanation in figure where the area of Patio has been divided into two rectangles
one of Dimension 35X20
Other of Dimension 15X20

As mentioned Patio is a square , Area of a square is S^2
All sides should be same as Square
Then how can we multiply Individual Areas 20x15 and 20x35??
Pls explain. Thanks

Hey,

It is nowhere mentioned in the question that the Patio is a square.

I guess you must have got confused with the following line - "what is the area of the patio in square feet?"

This simply means that we need to find the area of the patio and the unit of the area is $$(feet)^2$$ and that will happen only when we express each of the sides of the patio in term of feet and not some other measurement like meters, centimeters etc.

Thanks,
Saquib
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Joined: 23 Jul 2016
Posts: 25
Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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07 Mar 2017, 04:44
patio has dimension 40*35
therefore area=1400
why the overlapped area has to subtracted from it?
even though the question asks what is area of patio
Intern
Joined: 03 Aug 2016
Posts: 40
Re: A flat patio was built alongside a house as shown in the figure above. [#permalink]

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09 Apr 2018, 11:33
Bunuel wrote:

A flat patio was built alongside a house as shown in the figure above. If all angles shown are right angles, what is the area of the patio in square feet?

(A) 800
(B) 875
(C) 1,000
(D) 1,100
(E) 1,125

Kudos for a correct solution.

Attachment:
2015-10-15_0834.png

Area of the patio (including the part overlapped by the house) = L*W = 35*40 = 1400

Now, the area (square) of the overlapped part = side*side = 20*20 = 400

Area of the patio = 1400-400 = 1000

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Re: A flat patio was built alongside a house as shown in the figure above.   [#permalink] 09 Apr 2018, 11:33
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