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a function f(n) is defined as 1/n when n is an integer

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a function f(n) is defined as 1/n when n is an integer  [#permalink]

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New post 02 Jan 2019, 08:21
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

74% (01:28) correct 26% (01:56) wrong based on 31 sessions

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A function f(n) is defined as \(\frac{1}{n}\) when n is an integer and as 9n when n is a fraction. What is the value of f(f(f(f(\(\frac{1}{3^5}\)))))

A. \(\frac{1}{9}\)

B. \(\frac{1}{3}\)

C. 1

D. 3

E. 9

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Re: a function f(n) is defined as 1/n when n is an integer  [#permalink]

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New post 02 Jan 2019, 20:49
A function f(n) is defined as 1/n when n is an integer and is 9n when n is a fraction. What is the value of \(f(f(f(f(1/(3^5)))))\)

\(f(1/3^5) = 9*(1/3^5)\)
= \(1/3^3\) --------------Since n is fraction

\(f(1/3^3) = 9*(1/3^5)\)
= \(1/3\)

\(f(1/3) = 9*(1/3)\)
= 3
f(3) = 1/3 --------------- since n is an integer f(n) = 1/n

Option B is correct
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Re: a function f(n) is defined as 1/n when n is an integer  [#permalink]

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New post 03 Jan 2019, 08:14
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I'd probably rephrase the question to read A function f(n) is defined as 1/n when n is an integer and is 9n when n is a non-integer
All integers can be written as fractions (e.g., 3 = 3/1 = 6/2 = 21/7 = . . . )

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Re: a function f(n) is defined as 1/n when n is an integer   [#permalink] 03 Jan 2019, 08:14
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