Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.- Dec 14
11:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
04 May 2016, 07:35
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
29% (02:15) correct
71%
(02:27)
wrong
based on 227
sessions
History
Date
Time
Result
Not Attempted Yet
A piece of work can be done by 10 boys in 6 days working 4 hours each day. How many minimum possible number of boys are needed to complete another work which is three times more if they work for same integer number of hour and day, say x hour and x days?
(1) 5
(2) 10
(3) 12
(4) 15
(5) 30
(1) 5
(2) 10
(3) 12
(4) 15
(5) 30
04 May 2016, 08:01
Kudos
Bookmarks
Total work done = 10 * 6 * 4 = 240 units
New work = Three times more than current work
New work = Current work + 3(Current work)
New work = 4*240 = 960 units
Number of boys * x * x = 960
960 can be factorized as 2^6 * 3 * 5 --> 2^6 can be expressed as x^2 i.e. (2^3)^2
Minimum number of boys = 3 * 5 = 15
Answer: D
New work = Three times more than current work
New work = Current work + 3(Current work)
New work = 4*240 = 960 units
Number of boys * x * x = 960
960 can be factorized as 2^6 * 3 * 5 --> 2^6 can be expressed as x^2 i.e. (2^3)^2
Minimum number of boys = 3 * 5 = 15
Answer: D
General Discussion
06 May 2016, 22:47
Kudos
Bookmarks
Vyshak -- I understand everything up to: "# of boys * x * x = 960"
How are you able to replace (2^3)^2 for x^2 like that? I'd think each boy does (1)(6)(4) = 24 units of work, so 960 / 24 = 40 boys
Can you help me understand please? Thank you :D
Michael
How are you able to replace (2^3)^2 for x^2 like that? I'd think each boy does (1)(6)(4) = 24 units of work, so 960 / 24 = 40 boys
Can you help me understand please? Thank you :D
Michael
