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Re: A rectangle the length of which is 8 inches and the width of which is [#permalink]
This can be solved by a little bit of geometry,
Consider ABCD as the rectangle. The length of the diagonal will 10 units.
Required ans 10 + 2(corners) = 12.
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Re: A rectangle the length of which is 8 inches and the width of which is [#permalink]
Aviralft9 wrote:
This can be solved by a little bit of geometry,
Consider ABCD as the rectangle. The length of the diagonal will 10 units.
Required ans 10 + 2(corners) = 12.


Can you explain how will the diag. pass through the 2 additional tiles in the corner? I'm unable to get that bit.

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Re: A rectangle the length of which is 8 inches and the width of which is [#permalink]
Aviralft9 wrote:
This can be solved by a little bit of geometry,
Consider ABCD as the rectangle. The length of the diagonal will 10 units.
Required ans 10 + 2(corners) = 12.


That logic makes no sense, it just happens to be correct.
If i take a 4x4 square or 2x2 square the number of 1x1 squares the diagonal goes through are 4 and 2, respectively.
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Re: A rectangle the length of which is 8 inches and the width of which is [#permalink]
I drew a rough sketch. The slope of the line using point slope formula will give you 3/4=m. When X=1, Y=3/4, when X=2, Y= 1.5. A line going from the origin through those two points will go through 3 squares. So every 2 increases in X equals 3 squares it passes through.

=8/2=4 and 4*3=12.

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Re: A rectangle the length of which is 8 inches and the width of which is [#permalink]
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