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27 Nov 2018, 05:41
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Say our list is:
a, b, c, d, e, f, g, h, i, j, k, l, m, n, o
I just took the first four numbers and proved a=d. There's nothing special about the first four numbers in the list; I can use the same logic to prove that any two numbers are equal here. For example, if I want to prove that b=d, we have
b + c + a = 12
d + c + a = 12
Subtract the second equation from the first:
b - d = 0
b = d
So now we know that b = d. Since we saw that a=d as well, a, b and d are all equal. We can do this for all the letters in the list, so they all must be equal.
totoma97
Joined: 06 Apr 2019
Last visit: 17 Jun 2020
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Location: Italy
Concentration: Accounting, General Management
Schools: HEC Montral MS IB "22 (A)
GPA: 3
14 May 2019, 10:06
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If the sum of ANY 3 numbers is 12 , is not possible that the first number will be 3 the second 4 and the third 5?
14 May 2019, 19:12
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totoma97
Hi totoma97,
The example that you describe does NOT fit the given information. Fact 2 tells us that the sum of ANY 3 values will equal 12. Imagine if you had one 3, one 5 and a lot of 4s. It's certainly possible that you could select the one 3, the one 5 and a 4.... but what if you DON'T (you could potentially select one 3 and two 4s... and that sum is NOT 12). Thus, this example is NOT possible given the 'restriction' in Fact 2, so you cannot use it.
GMAT assassins aren't born, they're made,
Rich
