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Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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24 Jan 2016, 20:47
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Does there exist an integer d such that x > d > 1 and x/d is an integer? (1) 11! + 2 < x < 11!+ 12 (2) x > 2^5
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Last edited by ENGRTOMBA2018 on 24 Jan 2016, 21:33, edited 1 time in total.
Reformatted the question and added the OA.



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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24 Jan 2016, 21:03
noyaljoseph wrote: Does there exist an integer d such that x > d > 1 and x/d is an integer?
(1) 11! + 2 <x< 11!+ 12 (2) x > 2 5 Hi, The gap between 2 and 5 in x> 2 5, suggests something is missing in statement 2.. PL provide OA too.. now if we look at x > d > 1 and x/d is an integer, it means d should be a factor of x.. lets see the choices now.. (1) 11! + 2 <x< 11!+ 12 here I take x too be an integer, that is what it should be logically..any number say 11!+3 will have 3 as a factor 11!+4 will have 4 as a factor till 11!+ 11 will have a factor 11.. so ans is YES x/d can be an integer.. Suff.. (2) x > 2 5 In the way it is written it will be insuff.. when x is a prime, d cannot have any value ... so x/d will not be an integer NO if x is not a prime, then there will always be a d such that x/d is an int.. YES different answers possible Insuff A
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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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24 Jan 2016, 21:38
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noyaljoseph wrote: Does there exist an integer d such that x > d > 1 and x/d is an integer?
(1) 11! + 2 < x < 11!+ 12 (2) x > 2^5 The very requirement of this question to find whether x has another integer such that x/d is an integer is the very definition of a prime number 'x ' that does not have an integer 'd' such that x/d is an integer. Thus the question is simply asking whether 'x' is a prime number. Per statement 1, you can very well see that 11!+2 will be divisible by 2 (as 11! = 1*2*3 ....10*11) and similarly all numbers from 11!+2 to 11!+ 12 will all be composites (or not prime). This this statement is sufficient. Per statement 2, x > 2^5. Clearly not sufficient as there will always be a prime number greater than a given number (without any other bounds). Not sufficient. Thus A is the correct answer. Hope this helps.



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Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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24 Jan 2016, 21:41
chetan2u wrote: here [color=#ff0000]I take x too be an integer, that is what it should be logically..
You are correct for this assumption (it's more of a given) as it is given that d is an integer and x/d is also an integer. Thus these conditions are only possible when x is also an integer.



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Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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24 Jan 2016, 21:47
Engr2012 wrote: chetan2u wrote: here [color=#ff0000]I take x too be an integer, that is what it should be logically..
You are correct for this assumption (it's more of a given) as it is given that d is an integer and x/d is also an integer. Thus these conditions are only possible when x is also an integer. Hi, it is not given that x/d is an integer, we have to find if x/d is an integer. The two things mean a lot different.. and I do not think if we are finding whether x/d is an integer, we can infer that x is an integer. this will be wrong interpretation. The Q is better with 'x as integer' stated clearly.
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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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25 Jan 2016, 05:56
chetan2u wrote: Engr2012 wrote: chetan2u wrote: here [color=#ff0000]I take x too be an integer, that is what it should be logically..
You are correct for this assumption (it's more of a given) as it is given that d is an integer and x/d is also an integer. Thus these conditions are only possible when x is also an integer. Hi, it is not given that x/d is an integer, we have to find if x/d is an integer. The two things mean a lot different.. and I do not think if we are finding whether x/d is an integer, we can infer that x is an integer. this will be wrong interpretation. The Q is better with 'x as integer' stated clearly. In a DS question, you can either prove the existence with absolute certainty or prove the absence with absolute certainty. Either way, you will have a sufficient statement. The way I have approached is the latter and hence I assumed that in order for x/d to be an integer with d as integer, x must be an integer > not prime (based on statement 1). Your approach and mine are thus different ways of approaching the same thing.



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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25 Jan 2016, 06:43
Engr2012 wrote: In a DS question, you can either prove the existence with absolute certainty or prove the absence with absolute certainty. Either way, you will have a sufficient statement. The way I have approached is the latter and hence I assumed that in order for x/d to be an integer with d as integer, x must be an integer > not prime (based on statement 1). Your approach and mine are thus different ways of approaching the same thing. In a DS Q, the biggest traps are these only, where you are expected to believe/assume a variable as an integer. the same Q with a choice 1. x is a reciprocal of a prime number.here you can say that x/d is not an integer since the numerator is a fraction and the denominator is an integer...This statement will be sufficient to tell you that x/d is not an integer and will be suff..
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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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02 Feb 2016, 06:20
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I was confused by the wording of this question. What does "Does there exist an integer" exactly mean? Does it mean, "Is there at least one integer that exists?", or does it mean "Is there one and only one integer that exists?"



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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03 Feb 2016, 05:31
etdenlinger wrote: I was confused by the wording of this question. What does "Does there exist an integer" exactly mean? Does it mean, "Is there at least one integer that exists?", or does it mean "Is there one and only one integer that exists?" It would mean atleast one and not one only. Had it been 'one only', the question would have stated such a thing.



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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03 Feb 2016, 10:29
noyaljoseph wrote: Does there exist an integer d such that x > d > 1 and x/d is an integer?
(1) 11! + 2 < x < 11!+ 12 (2) x > 2^5 Composite number is a number that has more than 2 distinct factors.Question REPHRASED : Is x a composite Number ?Statement 1: 11! + 2 < x < 11!+ 12i.e. x = 11! + 2 but 11! is a multiple of 2 i.e. x is a multiple of 2 hence Yes a Composite Number i.e. x = 11! + 3 but 11! is a multiple of 3 i.e. x is a multiple of 3 hence Yes a Composite Number ..... ..... and so on.... i.e. x = 11! + 12 but 11! is a multiple of 12 i.e. x is a multiple of 12 hence Yes a Composite Number i.e. x is always a composite number. Hence, SUFFICIENT Statement 2: x > 2^5x is greater than 32 i.e. x may or may not be a Composite Number NOT SUFFICIENT Answer: Option A
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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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18 Jan 2018, 12:19
I had a quick question in regards to the "does there exist an integer" portion of the question.
From this given info, I can gather that the question is asking if there is atleast one integer D that makes X/D an integer. I understand why statement 1 is SUF but could one make the argument that statement 2 could also be SUF making the answer choice D?
If X > 2^5, there is at least one value for X, despite the fact that X can be a composite or prime, where X/D is an integer. I understand that this question is testing the properties of prime numbers but the "does there exist an integer" portion is throwing me a loop.



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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18 Jan 2018, 23:36
Jkim56 wrote: I had a quick question in regards to the "does there exist an integer" portion of the question.
From this given info, I can gather that the question is asking if there is atleast one integer D that makes X/D an integer. I understand why statement 1 is SUF but could one make the argument that statement 2 could also be SUF making the answer choice D?
If X > 2^5, there is at least one value for X, despite the fact that X can be a composite or prime, where X/D is an integer. I understand that this question is testing the properties of prime numbers but the "does there exist an integer" portion is throwing me a loop. Hi The second statement is NOT sufficient. Ok x > 2^5 or x > 32. Now if x = 33, then of course there exist a few integers between 1 and x which are factors of x (3, 11) But if x = 37, then since x is prime, there is NO integer between 1 and x which is a factor of x. we are not given whether x is prime or not. So second statement does not suffice.



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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03 Mar 2018, 12:17
GMATinsight wrote: noyaljoseph wrote: Does there exist an integer d such that x > d > 1 and x/d is an integer?
(1) 11! + 2 < x < 11!+ 12 (2) x > 2^5 Composite number is a number that has more than 2 distinct factors.Question REPHRASED : Is x a composite Number ?Statement 1: 11! + 2 < x < 11!+ 12i.e. x = 11! + 2 but 11! is a multiple of 2 i.e. x is a multiple of 2 hence Yes a Composite Number i.e. x = 11! + 3 but 11! is a multiple of 3 i.e. x is a multiple of 3 hence Yes a Composite Number ..... ..... and so on.... i.e. x = 11! + 12 but 11! is a multiple of 12 i.e. x is a multiple of 12 hence Yes a Composite Number i.e. x is always a composite number. Hence, SUFFICIENT Statement 2: x > 2^5x is greater than 32 i.e. x may or may not be a Composite Number NOT SUFFICIENT Answer: Option A Hi. But when we say x may or may not have a prime number but still there is an integer d ( i.e. for x =36, integer d is 9) such that x/d is an integer. Please help. Posted from my mobile device



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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04 Mar 2018, 11:10
Mudit27021988 wrote: GMATinsight wrote: noyaljoseph wrote: Does there exist an integer d such that x > d > 1 and x/d is an integer?
(1) 11! + 2 < x < 11!+ 12 (2) x > 2^5 Composite number is a number that has more than 2 distinct factors.Question REPHRASED : Is x a composite Number ?Statement 1: 11! + 2 < x < 11!+ 12i.e. x = 11! + 2 but 11! is a multiple of 2 i.e. x is a multiple of 2 hence Yes a Composite Number i.e. x = 11! + 3 but 11! is a multiple of 3 i.e. x is a multiple of 3 hence Yes a Composite Number ..... ..... and so on.... i.e. x = 11! + 12 but 11! is a multiple of 12 i.e. x is a multiple of 12 hence Yes a Composite Number i.e. x is always a composite number. Hence, SUFFICIENT Statement 2: x > 2^5x is greater than 32 i.e. x may or may not be a Composite Number NOT SUFFICIENT Answer: Option A Hi. But when we say x may or may not have a prime number but still there is an integer d ( i.e. for x =36, integer d is 9) such that x/d is an integer. Please help. Posted from my mobile deviceHi Your query is not clear? Can you please rephrase what you want to know? from first statement, it is clear that X is a composite number. So definitely there would be a positive integer greater than 1 but less than X which will be a factor of X.



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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04 Mar 2018, 12:07
amanvermagmat Thanks for getting back. I think I usually get too stuck with the language of question. My doubt was again with the question stem, since question stem says " does there exist an integer d" from which I understand to be,if there is any one such value that makes statement ( either statement 1 or 2) true, then it is sufficient to answer that yes! The value exists. In statement 2, like I mentioned , there are many values that exist for x>32 and for which x/d is an integer. Isnt it sufficient to answer that "yes! Value exists for x>32 where d/x is integer. Hence statement is sufficient". I understand the solution that is presented. I will be thankful if I can be provided some useful link to clear my thoughts on language of quant questions posed. Posted from my mobile device



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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05 Mar 2018, 22:59
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Mudit27021988 wrote: amanvermagmat Thanks for getting back. I think I usually get too stuck with the language of question. My doubt was again with the question stem, since question stem says " does there exist an integer d" from which I understand to be,if there is any one such value that makes statement ( either statement 1 or 2) true, then it is sufficient to answer that yes! The value exists. In statement 2, like I mentioned , there are many values that exist for x>32 and for which x/d is an integer. Isnt it sufficient to answer that "yes! Value exists for x>32 where d/x is integer. Hence statement is sufficient". I understand the solution that is presented. I will be thankful if I can be provided some useful link to clear my thoughts on language of quant questions posed. Posted from my mobile device Hello In statement 2, you are correct that many values exist for x>32 for which we will be able to find an integer 'd' such that x/d is an integer. But lets look at the question. The question says, "Does there exist an integer d such that x > d > 1 and x/d is an integer?" Unless we know what is 'x', how do we know whether such a 'd' exists or not. We are given that x>32. Say x=33, then definitely there exists a 'd' (3 or 11). But if x=41, then there does not exist such a 'd'. So it comes down to just one thing: we are NOT able to answer with a clearcut YES or a clearcut NO. Thats why statement 2 is not sufficient. As for the highlighted part in your quote (I have highlighted), I think understanding questions and explanations here on Gmatclub will be the best thing to do. Ask questions, and try to understand the replies, maybe that will help you understand steadily over a short period of time.



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Re: Does there exist an integer d such that x > d > 1 & x/d is an integer? [#permalink]
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07 Mar 2018, 22:53
amanvermagmat wrote: Mudit27021988 wrote: amanvermagmat Thanks for getting back. I think I usually get too stuck with the language of question. My doubt was again with the question stem, since question stem says " does there exist an integer d" from which I understand to be,if there is any one such value that makes statement ( either statement 1 or 2) true, then it is sufficient to answer that yes! The value exists. In statement 2, like I mentioned , there are many values that exist for x>32 and for which x/d is an integer. Isnt it sufficient to answer that "yes! Value exists for x>32 where d/x is integer. Hence statement is sufficient". I understand the solution that is presented. I will be thankful if I can be provided some useful link to clear my thoughts on language of quant questions posed. Posted from my mobile device Hello In statement 2, you are correct that many values exist for x>32 for which we will be able to find an integer 'd' such that x/d is an integer. But lets look at the question. The question says, "Does there exist an integer d such that x > d > 1 and x/d is an integer?" Unless we know what is 'x', how do we know whether such a 'd' exists or not. We are given that x>32. Say x=33, then definitely there exists a 'd' (3 or 11). But if x=41, then there does not exist such a 'd'. So it comes down to just one thing: we are NOT able to answer with a clearcut YES or a clearcut NO. Thats why statement 2 is not sufficient. As for the highlighted part in your quote (I have highlighted), I think understanding questions and explanations here on Gmatclub will be the best thing to do. Ask questions, and try to understand the replies, maybe that will help you understand steadily over a short period of time. Thanks amanvermagmat for such a wonderful piece of advice and explanation. +1 for the same




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